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4 years ago

According to Coulomb’s Law which of the following statements are correct? Select all that apply.

2 answers:

5 0

The correct options are:
1) The force between two charged objects increases as the charge of either one of the objects is increased.
4) The force between two charged objects increases as the objects are placed closer together.

In fact, the electrostatic force is given by Coulomb's law:
 $F=k \frac{q_1 q_2}{r^2}$
where k is the Coulomb's constant, q1 and q2 are the two charges, r is the separation between the two charges. As we can see from the equation, if one of the charges (q1 or q2) is increased, than the force increases as well (so statement 1) is correct), and if the two objects are placed closer together (r is decreased), the force F increases as well (so statement 4 is correct as well)

nikdorinn [45]4 years ago

5 0

The force between two charged objects increases as the charge of either one of the object is increased

the force between two charged objects increases as the object are placed closer together

is the right answer

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Why does the bottom of a swimming pool always appear shallower than it actually is

emmainna [20.7K]

Answer:

The refraction of light at the surface of water makes ponds and swimming pools appear shallower than they really are.

Explanation:

so its just the refraction of light at the surface

8 0

3 years ago

Read 2 more answers

Mathematically, explain how a car (A) with mass of 500 kg and velocity of 2 m/s has the same kinetic energy as a car (B) with ma

scoray [572]

Answer:

Both kinetic energies are equal

Explanation:

Kinetic Energy

Is the type of energy of an object due to its state of motion. It's proportional to the mass and the square of the speed.

The equation for the kinetic energy is:

$\displaystyle K=\frac{1}{2}mv^2$

Where:

m = mass of the object

v = speed of the object

The kinetic energy is expressed in Joules (J)

There are two cars:

Car (A) with mass ma=500 kg and speed va= 2 m/s

Car (B) with mass mb=20,000 gr and speed vb= 10 m/s

Calculate the kinetic energy of both cars:

$\displaystyle K_a=\frac{1}{2}m_av_a^2$

$\displaystyle K_a=\frac{1}{2}500*2^2$

$\displaystyle K_a=250*4=1,000 J$

To calculate the Kb, the mass must be expressed in kg:

mb=20,000/1,000 =20 Kg

$\displaystyle K_b=\frac{1}{2}m_bv_b^2$

$\displaystyle K_b=\frac{1}{2}20*10^2$

$\displaystyle K_b=10*100=1,000 J$

Both kinetic energies are equal

8 0

3 years ago

PLEASE SOLVE QUICKLY!!! Solve for A, B, and C from graph

hram777 [196]

A = 59.35cm

B = 196.56g

C = 74.65g

Explanation:

We know,

$x = \frac{L}{\frac{W}{F} +1}$

and L = x+y

Total length, L = 100cm

Weight of Beam, W = 71.8g

Center of mass, x = 49.2cm

Added weight, F = 240g

Position weight placed from fulcrum, y = ?

$L-y = \frac{L}{\frac{W}{F}+1 } \\100 - y = \frac{100}{\frac{71.8}{49.2}+1 } \\100 - y = \frac{100}{1.46+1}\\\\100 - y = \frac{100}{2.46} \\100-y = 40.65\\\\y = 59.35cm$

Therefore, position weight placed from fulcrum is 59.35cm

Total length, L = 100cm

Center of mass, x = 47.8 cm

Added weight, F = 180g

Position weight placed from fulcrum, y = 12.4cm

Weight of Beam, W = ?

$47.8 = \frac{100}{\frac{W}{180}+1 }\\\47.8 = \frac{100}{\frac{W+180}{180} } \\\\47.8 = \frac{100 X 180}{W+180}\\ \\47.8W + 47.8 X 180 = 18000\\47.8W = 18000 - 8604\\W = \frac{9396}{47.8}\\ W = 196.56g$

Therefore, weight of the beam is 196.56g

Total length, L = 100cm

Center of mass, x = 50.8 cm

Position weight placed from fulcrum, y = 9.8cm

Weight of Beam, W = 72.3g

Added weight, F = ?

$50.8 = \frac{100}{\frac{72.3}{F}+1 }\\\ 50.8 = \frac{100}{\frac{72.3+F}{F} } \\\\50.8 = \frac{100 X F}{72.3+F}\\ \\50.8 X 72.3 + 50.8 X F = 100F\\\\3672.84 = 100F-50.8F\\3672.84 = 49.2F\\F = 74.65g$