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4 years ago

What is the Calvin cycle and why is it essential for the transfer of energy during photosynthesis

2 answers:

8 0

Calvin Cycle is the part of the process of photosynthesis, by which Plant makes Food (Glucose), it is independent of the light. It is essential as it is the primary source of energy on the earth

Hope this helps!

svetlana [45]4 years ago

3 0

Calvin cycle is the part of the process of photosynthesis, by which plant makes food (Glucose) ,it is independent of the light. it is essential as it is the primary source of energy on earth.

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An astronaut on the moon throws a baseball upward. The astronaut is 6 ft, 6 in. tall, and the initial velocity of the ball is

KatRina [158]

Answer: 89.803 ft

Explanation:

The complete question is written below:

An astronaut on the moon throws a baseball upward. The astronaut is 6ft, 6 in. tall and the initial velocity of the ball is 30 ft per second. The height s of the ball in feet is given by the equation,s=-2.7t^2+30t+6.5, where t is the number of seconds after the ball is thrown.

The ball will never reach a height of 100ft. How can this be determined algebraically?

We have the following equation that expresses the height $s$ as a function of time:

$s=-2.7t^{2}+30t+6.5$ (1)

Now, if we wan to find the maximum height the baseball reaches and prove it is less than 100 ft, we firstly have to find the time $t_{total}$ the whole parabolic movement lasts and then find $t_{smax}=\frac{t_{total}}{2}$ which is the time it takes the baseball to reach its maximum height.

So, if we want to calculate $t_{total}$ , this is fulfilled when $s=0$ , when the baseball hits the ground:

$0=-2.7t^{2}+30t+6.5$ (2)

This is a quadratic equation of the form $0=at^{2}+bt+c$ , and we have to use the quadratic formula if we want to find $t_{total}$ :

$t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$ (3)

Where $a=-2.7$ , $b=30$ , $c=6.5$

Substituting the known values and choosing the positive result of the equation:

$t_{total}=11.323 s$ (4)

Then we can calculate $t_{smax}$ :

$t_{smax}=\frac{t_{total}}{2}$ (5)

$t_{smax}=\frac{11.323 s}{2}$

$t_{smax}=5.661 s$ (6)

Substituting (6) in (1):

$s=-2.7(5.661 s)^{2}+30(5.661 s)+6.5$ (7)

$s=89.803 ft$ (8) This is the maximum height the baseball reaches, as we can see it is less than 100 ft

8 0

3 years ago

Two vectors pointing right starting at the same position. Vector A is on top and longer. Vector B is shorter and below.

Oksana_A [137]

Answer:

The displacements are not equal. While their direction is the same, their length (i.e., distance or magnitude) is not. A is longer than B.

Explanation:

correct on e2020- sample respnse

4 0

3 years ago

Read 2 more answers

A turntable, with a mass of 1.5 kg and diameter of 20 cm, rotates at 70 rpm on frictionless bearings. Two 540 g blocks fall from

ivann1987 [24]

Answer:

The turntable's angular speed after the event is 28.687 revolutions per minute.

Explanation:

The system formed by the turntable and the two block are not under the effect of any external force, so we can apply the Principle of Conservation of Angular Momentum, which states that:

$I_{T}\cdot \omega_{o} = (2\cdot r^{2}\cdot m +I_{T})\cdot \omega_{f}$ (1)

Where:

$I_{T}$ - Moment of inertia of the turntable, in kilogram-square meters.

$r$ - Distance of the block regarding the center of the turntable, in meters.

$m$ - Mass of the object, in kilograms.

$\omega_{o}$ - Initial angular speed of the turntable, in radians per second.

$\omega_{f}$ - Final angular speed of the turntable-objects system, in radians per second.

In addition, the momentum of inertia of the turntable is determined by following formula:

$I_{T} = \frac{1}{2}\cdot M\cdot r^{2}$ (2)

Where $M$ is the mass of the turntable, in kilograms.

If we know that $\omega_{o} \approx 7.330\,\frac{rad}{s}$ , $M = 1.5\,kg$ , $m = 0.54\,kg$ and $r = 0.1\,m$ , then the angular speed of the turntable after the event is: