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3 years ago

An Avon sales lady buys a make-up kit for $120 and sells it for $65 more. What is the percent of markup? 37.5%

Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

6 0

Answer: 54.2%

Step-by-step explanation:

The percent mark-up refers to how much higher you sell a product than what you bought it for expressed as a percentage of what you bought it for.

In this case, the woman bought it for $120 and sold it for $65 more.

Cost = $120

Markup = $65

Markup percentage = 65 / 120 * 100%

= 54.2%

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In a random sample of 62 professional actors, it was found that 40 were extroverts. Please find the point estimate, 95% confiden

den301095 [7]

The point Estimate is 0.645 , the confidence interval is (0.525 ,0.764).

<h3>What is Point Estimate ?</h3>

The point estimate is the proportion of success in the sample.

From the data given

p = 40/62

p = 0.645

The point Estimate is 0.645

(b) Confidence interval for true proportion is

$\rm {p -Z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}} , p +Z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}$

For 95 % Z = 1.96

p =0.645

1-p = 0.355

putting the values

$\rm {0.645 -1.96 \sqrt{\dfrac{0.645\times0.355}{62}} , {0.645 +1.96 \sqrt{\dfrac{0.645\times0.355}{62}} \\$

(0.525 , 0.764)

Lower Limit = 0.525

Upper Limit = 0.764

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2 years ago

4.3 Mr Mokwebo 's two sons, Refentse and Tokelo have just passed grade 7 and grade 9 respectively. He will give them some money

Bumek [7]

The amount of money each of Mr Mokwebo 's two sons; Tokelo and Refentse will get is R116 and R95 respectively.

<h3>How to write and solve equation:</h3>

Amount needed to buy chocolate = R253
Tokelo's money = x
Refentse's money = x - 21

Total amount needed = Tokelo's money + Refentse's money

253 = x + (x - 21)

253 = x + x - 21

253 = 2x - 21

253 - 21 = 2x

232 = 2x

divide both sides by 2

x = 232/2

x = 116

Therefore,

Tokelo's money = x = R116

Refentse's money = x - 21

= 116 - 21

= R95

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2 years ago

6x to the power of 2 + 7x to the power of 3 + 8x to the power of 5 + 9

Paha777 [63]

Answer:

I couldn't understand question paper plz can u give question with photo too.

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3 years ago

I don’t understand how to do this

schepotkina [342]

Answer:

The solution is $x =0.$

Step-by-step explanation:

The equation

$\bold{(1).}\: sin(\dfrac{3\pi }{2} +x)+sin(\dfrac{3\pi }{2} +x) =-2$

can be rewritten as

$2* sin(\dfrac{3\pi }{2} +2) =-2$

and can be further simplified to

$sin(\dfrac{3\pi }{2}+x ) =-1$ .

Now, taking the inverse sine of both sides we get:

$sin^{-1}(sin(\dfrac{3\pi }{2} +x) =sin^{-1}(-1)$

$\bold{(2).}\: \dfrac{3\pi }{2} +2 =sin^{-1}(-1)$

The value of the right side on the interval $[0,2\pi)$ is

$sin^{-1}(-1) = \dfrac{3\pi}{2} \: \:( \text{or }270^o)$ ,

which makes the equation (2)

$\dfrac{3\pi }{2}+x =\dfrac{3\pi}{2}$

solving for $x$ gives

$\boxed{x = 0}$

which is our solution.

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3 years ago

The distribution of IQ scores can be modeled by a normal distribution with mean 100 and standard deviation 15.

evablogger [386]

Answer:

4.4% of the population with IQ between 120 and 125.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100

Standard Deviation, σ = 15

We are given that the distribution of IQ scores is a bell shaped distribution that is a normal distribution.

a) Let X be a person's IQ score.

Then, density functions for IQ scores is given by:

$P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{z^2}{2}}\\\\\text{where,}\\\\z = \frac{x-\mu}{\sigma}\\\\P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{(x-\mu)^2}{2\sigma^2}}\\\\P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{(x-100)^2}{450}}$

b) P(population with IQ between 120 and 125.)

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

$P(120 \leq x \leq 125) = P(\displaystyle\frac{120 - 100}{15} \leq z \leq \displaystyle\frac{125-100}{15}) = P(1.33 \leq z \leq 1.66)\\\\= P(z \leq 1.66) - P(z < 1.33)\\= 0.952 - 0.908 = 0.044 = 4.4\%$

$P(120 \leq x \leq 125) = 4.4\%$

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3 years ago