Answer:
![\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D)
Step-by-step explanation:
We are required to simplify the quotient: ![\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B60%7D%20%7D%7B%5Csqrt%5B3%5D%7B20%7D%7D)
Since the <u>numerator and denominator both have the same root index</u>, we can therefore say:
![\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}} =\sqrt[3]{\dfrac{60} {20}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B60%7D%20%7D%7B%5Csqrt%5B3%5D%7B20%7D%7D%20%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B60%7D%20%7B20%7D%7D)
![=\sqrt[3]{3}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B3%7D)
The simplified form of the given quotient is .
Answer:
for four right angles, should be only square.
for all sides congruent, square and rhombus
for 2 pairs of parallel sides, parallelogram and rhombus and square.
for only 1 pair of congruent sides, parallelogram and rhombus
Step-by-step explanation: doggo has asian smarts, not bsian
To evaluate this expression, we need to remember that subtracting a negative number is the same as adding a positive number, and that adding a negative number is the same as subtracting a positive number. Using this knowledge, let's begin to simplify the expression below:
-1 - 3 - (-9) + (-5)
Because addition of a negative number is the same as subtraction of a positive number, we can change + (-5) to -5, as shown below:
-1 - 3 - (-9) - 5
Next, because we know that subtracting a negative number is the same as adding a positive number, we can change - (-9) to + 9, as shown below:
-1 - 3 + 9 - 5
Now, we can subtract the first two terms and begin to evaluate our expression:
-4 + 9 - 5
Next, we can add the first two numbers of the expression:
5 - 5
Now, we can subtract our last two numbers, which gives us our answer:
0
Therefore, your answer is 0.
Hope this helps!
A right triangle can also be an isosceles triangle.
