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Irina18 [472]
3 years ago
13

Peter draws two cards in a row from a deck of 52 cards. If Peter doesn't place the first card back in the deck, what is the prob

ability of drawing 2 red kings from the deck?
Mathematics
1 answer:
Nostrana [21]3 years ago
8 0

Answer:

S(n)=[50]

Step-by-step explanation:

52-2=50

so the S(n)=50

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Please help I will give brainliest <br> A.3<br> B.6<br> C. 9<br> D. 12
Katyanochek1 [597]

Answer:

A is the answer

3 0
3 years ago
Read 2 more answers
You need a 70% alcohol solution. On hand, you have a 420 mL of a 85% alcohol mixture. How much pure water will you need to add t
Nimfa-mama [501]

Answer:

Pure water =74.1 mL

Step-by-step explanation:

You need 420 mL of a 70% alcohol solution.

420 mL of solution and 70% of it should be alcohol.

So,

420 * 70/100 mL

= 420 * 0.7

= 294 mL of alcohol and the rest should be water.

On hand, you have a 85% alcohol mixture.

The alcohol can only come from the 85% mixture. So, how much of 85% alcohol do we need to get 294 mL of alcohol:

Let

y = alcohol solution needed

85% of y = 294

85/100 * y = 294

y = 294 ÷ 85/100

y = 294 × 100/85

y = 29,400/85

y = 345.88235294117

Approximately, 345.9mL

The rest of 420 mL solution has to be pure water

Pure water = 420 mL - 345.9mL

= 74.1 mL

Pure water =74.1 mL

6 0
3 years ago
A recent survey of 50 executives who were laid off during a recent recession revealed it took a mean of 26 weeks for them to fin
drek231 [11]

Answer:

The pvalue of 0.0113 < 0.05 means that there is sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance

Step-by-step explanation:

The null hypothesis is:

H_{0} = 28

The alternate hypotesis is:

H_{1} < 28

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

A recent survey of 50 executives who were laid off during a recent recession revealed it took a mean of 26 weeks for them to find another position.

This means that n = 50, X = 26

Assume the population standard deviation is 6.2 weeks.

This means that \sigma = 6.2

Does the data provide sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance

We have to find the pvalue of Z, looking at the z-table, when \mu = 28. It if is lower than 0.05, it provides evidence.

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{26 - 28}{\frac{6.2}{\sqrt{50}}}

z = -2.28

z = -2.28 has a pvalue of 0.0113 < 0.05.

The pvalue of 0.0113 < 0.05 means that there is sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance

5 0
3 years ago
What is the interquartile range for this data set? 9, 17, 3, 26, 9, 15, 7, 20, 5, 12, 22
stepan [7]
23 because you subtract your highest number with your lowest number
4 0
3 years ago
Read 2 more answers
What is (2v+5)(2v-5)
DedPeter [7]

Answer:

4v^2-25

Step-by-step explanation:

(2v+5)(2v-5)

Using (a-b)(a+b)=a^2-b^2, simplify the product

(2v)^2-5^2

To raise a <u>product to a power</u>, raise each factor to that power.

4v^2-5^2

Evaluate the <u>power.</u>

4v^2-25

3 0
3 years ago
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