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GenaCL600 [577]
3 years ago
10

I don’t understand how to do this

Mathematics
1 answer:
schepotkina [342]3 years ago
4 0

Answer:

The solution is x =0.

Step-by-step explanation:

The equation

\bold{(1).}\: sin(\dfrac{3\pi }{2} +x)+sin(\dfrac{3\pi }{2} +x) =-2

can be rewritten as

2* sin(\dfrac{3\pi }{2} +2) =-2

and can be further simplified to

sin(\dfrac{3\pi }{2}+x ) =-1.

Now, taking the inverse sine of both sides we get:

sin^{-1}(sin(\dfrac{3\pi }{2} +x) =sin^{-1}(-1)

\bold{(2).}\:  \dfrac{3\pi }{2} +2 =sin^{-1}(-1)

The value of the right side on the interval [0,2\pi) is

sin^{-1}(-1) = \dfrac{3\pi}{2} \: \:( \text{or }270^o) ,

which makes the equation (2)

\dfrac{3\pi }{2}+x  =\dfrac{3\pi}{2}

solving for x gives

\boxed{x = 0}

which is our solution.

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