Answer:
cvp B çünkü o iki kavram birbiriyle eşit
Answer:
<u><em>The equation is y = (1/2)x + - 3.5</em></u>
Step-by-step explanation:
We look for an equation with the form y = mx + b, where m is the slope and b the y-intercept.
We're given the slope, (1/2) which we can use for m:
y = (1/2)x + b
We are told the line goes through (5,-1). We need a value of b that will move the line to include this point. Do that by substituting the values:
x = 5, and y= -1
y = (1/2)x + b
-1 = (1/2)*5 + b
-1 = (2.5) + b
- 3.5 = b
<u><em>The equation is y = (1/2)x + - 3.5</em></u>
See the attached image.
Answer:
the first one is -9/40. the second one is 109/20. the third one is -8/35.
Step-by-step explanation:
here is the work for the first one 3/8-.6 and convert into a simplified fraction and came up with -9/40. here is the work for the second one 4 4/3+0.7 and then convert into a simplified fraction and came up with 109/20. here is the work for the third one 4/7-0.8 and then convert into a simplified fraction and came up with -8/35.
Answer:
maximum height is 4.058 metres
Time in air = 0.033 second
Step-by-step explanation:
Given that the equation height h
h = -212t^2 + 7t + 4
What is the toy's maximum height?
Let us assume that the equation is a perfect parabola
Time t at Maximum height will be
t = -b/2a
Where b = 7 and a = - 212
t = -7/ - 212 ×2
t = 7/ 424 = 0.0165s
Substitute t in the main equation
h = - 212(7/424)^2 + 7(7/424) + 4
h = - 0.05778 + 0.115567 + 4
h = 4.058 metres
Therefore the maximum height is 4.058 metres
How long is the toy in the air?
The object will go up and return to the ground.
At ground level, h = 0
-212t^2 + 7t + 4 = 0
212t^2 - 7t - 4 = 0
You can factorize the above equation and pick the positive time t since time can't be negative
Or
Since we have assumed that it's a perfect parabola,
Total time in air = (-b/2a) × 2
Time in air = 0.0165 × 2 = 0.033 s