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Mama L [17]
3 years ago
7

What is the area of this figure?

Mathematics
1 answer:
Dima020 [189]3 years ago
4 0

Answer:

220.5 \:  {yd}^{2}

Step-by-step explanation:

Area of the figure = Area of the arc with radius 10 yd and central angle 90° + Area of rectangle with dimensions (10 + 5 - 3 = 12) 12 yd and (7 + 6 - 4 = 9) 9 yd + Area of square with dimension 4yd + Area of rectangle with dimensions 3 yd by 2 yd + Area of triangle with base 3 yd and height (5 + 3 = 8) 8 yd.

=  \frac{90 \degree}{360 \degree}  \times 3.14 {(10)}^{2}  + 12 \times 9 +  {4}^{2} \\ + 3 \times 2 +  \frac{1}{2}  \times 3 \times 8 \\  \\  =  \frac{1}{4}  \times 314 + 108 + 16 + 6 + 12 \\  \\  = 78.5 + 142 \\  \\  = 220.5 \:  {yd}^{2}

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3 years ago
Mr.Gleason's math class lasts 40 minutes.Math class starts at 9:55 A.M. At what time does math class end?
klio [65]
Math class ends at 10:35 am
5 0
3 years ago
Read 2 more answers
Graph the line with slope 1/2 passing through the point (5, - 1)
True [87]

Answer:

<u><em>The equation is y = (1/2)x + - 3.5</em></u>

Step-by-step explanation:

We look for an equation with the form y = mx + b, where m is the slope and b the y-intercept.

We're given the slope, (1/2) which we can use for m:

y = (1/2)x + b

We are told the line goes through (5,-1).  We need a value of b that will move the line to include this point.  Do that by substituting the values:

 x = 5, and y= -1

y = (1/2)x + b

-1 = (1/2)*5 + b

-1 = (2.5) + b

- 3.5 =   b

<u><em>The equation is y = (1/2)x + - 3.5</em></u>

See the attached image.

7 0
1 year ago
Simplify ech answer into a fraction, Show all work please!
Gnom [1K]

Answer:

the first one is -9/40. the second one is 109/20. the third one is -8/35.

Step-by-step explanation:

here is the work for the first one 3/8-.6 and convert into a simplified fraction and came up with -9/40. here is the work for the second one 4 4/3+0.7 and then convert into a simplified fraction and came up with 109/20. here is the work for the third one 4/7-0.8 and then convert into a simplified fraction and came up with -8/35.

6 0
3 years ago
Task 1:
OleMash [197]

Answer:

maximum height is 4.058 metres

Time in air = 0.033 second

Step-by-step explanation:

Given that the equation height h

h = -212t^2 + 7t + 4

What is the toy's maximum height?

Let us assume that the equation is a perfect parabola

Time t at Maximum height will be

t = -b/2a

Where b = 7 and a = - 212

t = -7/ - 212 ×2

t = 7/ 424 = 0.0165s

Substitute t in the main equation

h = - 212(7/424)^2 + 7(7/424) + 4

h = - 0.05778 + 0.115567 + 4

h = 4.058 metres

Therefore the maximum height is 4.058 metres

How long is the toy in the air?​

The object will go up and return to the ground.

At ground level, h = 0

-212t^2 + 7t + 4 = 0

212t^2 - 7t - 4 = 0

You can factorize the above equation and pick the positive time t since time can't be negative

Or

Since we have assumed that it's a perfect parabola,

Total time in air = (-b/2a) × 2

Time in air = 0.0165 × 2 = 0.033 s

3 0
3 years ago
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