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katrin2010 [14]
3 years ago
12

Joan mails a package that weighs 140 G about how many ounces is thepackage use 1 oz equals 28.4 gram

Mathematics
1 answer:
Marina86 [1]3 years ago
5 0

Answer:

The package is about 4.9\ oz

Step-by-step explanation:

we know that

Using proportion

\frac{1}{28.4}\frac{oz}{g}=\frac{x}{140}\frac{oz}{g}\\ \\x=140/28.4\\ \\x=4.9\ oz

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Alexxandr [17]

Answer:

7x=−x+24 7 x = − x + 24  

Step-by-step explanation:

The equations we solved in the last section simplified nicely so that we could use the. Our strategy will involve choosing one side of the equation to be the variable side, and step by step, to isolate the variable terms on one side of the equation

7 0
2 years ago
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A.8.4 t=_______kg
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<h2><u>ANS</u></h2>

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7 0
3 years ago
Daniel paid interest of 1,020 in 5years at12%per annum on a loan. Hw much did he borrow
Marat540 [252]
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5 0
2 years ago
Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview
svetlana [45]

Answer:  The required solution is

y=(-2+t)e^{-5t}.

Step-by-step explanation:   We are given to solve the following differential equation :

y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)

Let us consider that

y=e^{mt} be an auxiliary solution of equation (i).

Then, we have

y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.

Substituting these values in equation (i), we get

m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.

So, the general solution of the given equation is

y(t)=(A+Bt)e^{-5t}.

Differentiating with respect to t, we get

y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.

According to the given conditions, we have

y(0)=-2\\\\\Rightarrow A=-2

and

y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.

Thus, the required solution is

y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.

6 0
3 years ago
Find the domain and range of the following graph.
shutvik [7]

Remember that the <em>domain</em> is the set of all the x terms.

So in the graph shown here, notice that the x terms seem to be increasing in both a positive and negative direction and there seems to be no limit to how large or how small the x terms can get. So the x terms can be all positive and negative numbers, including decimals and fractions.

In other words, the x terms can be All Real Numbers.

So the domain is equal to the set of all real numbers or <em>R</em>.

The range is the set of all the y terms.

Notice that all the y terms are less than or equal to 9.

So the range is {y: y ≤ 9}.

8 0
3 years ago
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