The number 4,278 I think.
Hope this helps!
Answer:
531441
Step-by-step explanation:
We can find by factorization
531441 = 9 * 9 * 9 * 9 * 9 *9 = (9*9*9) * (9*9*9)
![\sqrt[3]{531441}=\sqrt[3]{9*9*9*9*9*9} =9*9 = 81\\\\\\\sqrt{531441}=\sqrt{(9*9)*(9*9)*(9*9)}=9*9*9=729](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B531441%7D%3D%5Csqrt%5B3%5D%7B9%2A9%2A9%2A9%2A9%2A9%7D%20%20%3D9%2A9%20%3D%2081%5C%5C%5C%5C%5C%5C%5Csqrt%7B531441%7D%3D%5Csqrt%7B%289%2A9%29%2A%289%2A9%29%2A%289%2A9%29%7D%3D9%2A9%2A9%3D729)
Answer:
Step-by-step explanation:
Using the normal distribution, it is found that there is a 0.877 = 87.7% probability of a bulb lasting for at most 569 hours.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The probability of a bulb lasting for at most 569 hours is the <u>p-value of Z when X = 569</u>, hence:


Z = 1.16
Z = 1.16 has a p-value of 0.877.
0.877 = 87.7% probability of a bulb lasting for at most 569 hours.
More can be learned about the normal distribution at brainly.com/question/24663213
#SPJ1
When calculating the average of individual data, you set of all observations of a given characteristic, usually in ascending order. The arithmetic mean for this series is calculated by summing the values of the observations and dividing the result by the number of observations.
Hope this helps, please give me brainliest