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Maslowich
3 years ago
9

Funniest spongebob quote

Mathematics
2 answers:
KiRa [710]3 years ago
8 0

Answer: Evil

Step-by-step explanation:

Aleksandr [31]3 years ago
6 0

Answer: What the spongebob is evil?

Step-by-step explanation:

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In AABC, what is the value of cos B?<br>A. 5/13 B. 12/13 C. 5/12 D. 13/12​
Zielflug [23.3K]

Answer:

Option B ⇒ \frac{12}{13}

Step-by-step explanation:

Cos B = adjacent/hypotenuse

adjacent = 12

hypotenuse = 13

∴ cos B = 12/13

The answer is option B

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There is a reflection at the boundary between two materials if there is a change of __________ at the boundary.
gtnhenbr [62]

There is a reflection at the boundary between two materials if there is a change of<u> the speed of light in the material </u>at the boundary.

This bending is referred to as refraction. whilst a wave traveling at an angle adjusts its velocity upon crossing a boundary among materials,. This bending is known as refraction. As a wave crosses a boundary into a new medium, its pace, and wavelength exchange simultaneously as its frequency stays equal.

While light from air hits a smooth piece of glass (n = 1. five) with the ray perpendicular to the glass floor, of the subsequent will occur while light from air hits a clean piece of glass with the ray perpendicular to the glass surface, the part of the light passing into the glass: will now not exchange its frequency.

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Show Workings.<br>Question is in attached image.​
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Answer:

A.]A chord of a circle of diameter 40 cm subtends an angle of 70° at the centre of the circle.

Solution given;

diameter [d]=40cm

centre angle [C]=70°

(a) Find the perpendicular distance be tween the chord and the centre of the circle.

Answer:

we have

the perpendicular distance be tween the chord and the centre of the circle=[P]let

we have

P=d Sin (C/2)

=40*sin (70/2)

=22.9cm

<u>the</u><u> </u><u>perpendicular distance be tween the chord and the centre of the </u><u>circle</u><u> </u><u>is</u><u> </u><u>2</u><u>2</u><u>.</u><u>9</u><u>c</u><u>m</u><u>.</u>

(b) Using = 3.142, find the length of the minor arc.

Solution given;

minor arc=\frac{70}{360}*πd=\frac{7}{36}*3.142*40

=<u>2</u><u>4</u><u>.</u><u>4</u><u>4</u><u>c</u><u>m</u>

<u>the length of the minor arc.</u><u> </u><u>is</u><u> </u><u>2</u><u>4</u><u>.</u><u>4</u><u>4</u><u>cm</u><u>.</u>

B.]In the diagram, XZ is a diameter of the cir cle XYZW, with centre O and radius 15/2 cm.

If XY = 12 cm, find the area of triangle XYZ.

Solution given:

XY=12cm

XO=15/2cm

XZ=2*15/2=15cm

Now

In right angled triangle XOY [inscribed angle on a diameter is 90°]

By using Pythagoras law

h²=p²+b²

XZ²=XY²+YZ²

15²=12²+YZ²

YZ²=15²-12²

YZ=\sqrt{81}=9cm

:.

base=9cm

perpendicular=12cm

Now

Area of triangle XYZ=½*perpendicular*base

=½*12*9=54cm²

the area of triangle XYZ is <u>5</u><u>4</u><u>c</u><u>m</u><u>²</u><u>.</u>

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