The surface area of what?
The answer in itself is 1/128 and here is the procedure to prove it:
cos(A)*cos(60+A)*cos(60-A) = cos(A)*(cos²60 - sin²A)
<span>= cos(A)*{(1/4) - 1 + cos²A} = cos(A)*(cos²A - 3/4) </span>
<span>= (1/4){4cos^3(A) - 3cos(A)} = (1/4)*cos(3A) </span>
Now we group applying what we see above
<span>cos(12)*cos(48)*cos(72) = </span>
<span>=cos(12)*cos(60-12)*cos(60+12) = (1/4)cos(36) </span>
<span>Similarly, cos(24)*cos(36)*cos(84) = (1/4)cos(72) </span>
<span>Now the given expression is: </span>
<span>= (1/4)cos(36)*(1/4)*cos(72)*cos(60) = </span>
<span>= (1/16)*(1/2)*{(√5 + 1)/4}*{(√5 - 1)/4} [cos(60) = 1/2; </span>
<span>cos(36) = (√5 + 1)/4 and cos(72) = cos(90-18) = </span>
<span>= sin(18) = (√5 - 1)/4] </span>
<span>And we seimplify it and it goes: (1/512)*(5-1) = 1/128</span>
Answer:
m∠7 = 64°
Step-by-step explanation:
∠7 and ∠8 are supplementary meaning they add up to 180°.
m∠7 + m∠8 = 180°
m∠7 + 116° = 180°
m∠7 = 64°
<u>Answer-</u>
<u>Solution-</u>
Rational Root Theorem-
All the potential rational roots are,
The given polynomial is,
Here,
The potential rational roots are,
From, the given options only 
satisfies.
Answer:
First, plot the y-intercept. The y-intercept is 1, so plot the point (0,1).
Then go up 2 points and to the right 3 points and plot a point there. (3,3)
We go to the right because the slope is positive.
Draw a line through the two points.
Step-by-step explanation:
y = mx+b
m = slope
b = y-intercept
