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2 years ago

Please help me correct some answers on my test!! im really confused. please be serious, no weird answers

Mathematics

1 answer:

lys-0071 [83]2 years ago

5 0

The answer is 110 degrees.
250 + 110= 360
There’s 360 degrees in one whole circle :)

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A volleyball of radius 13 inches fits exactly in a cylinder with the same radius. inside the container there is empty space not

asambeis [7]

Volume of Sphere is V=(4/3)*PI*r^3

The radius of the volleyball is 13 inches

<span>So V=(4/3) * 3.14 * 13^3 = 9198 cubic inches</span>

Volume of a cylinder is V=pi * r^2 *h

Since they say the ball fits perfectly

The radius is 13 and the height is 26 ( the diameter of the ball)

So V=3.14 * 13^2 * 26 = 13,797 cubic inches

13797 – 9198 = 4,599 cubic inches of empty space

4 0

3 years ago

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State the domain and range<br> of f(x) = x²

ANTONII [103]

Answer:

Domain : All real numbers

Range: y >= 0

Step-by-step explanation:

4 0

2 years ago

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10(g+5)=2(g+9). <br> please help

MAVERICK [17]

Answer:

g=-4

Step-by-step explanation:

7 0

2 years ago

How do you do this ? Need some help ASAP!

Ivan

Answer:

On what

Step-by-step explanation:

6 0

2 years ago

Verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial 4x^3+20x^2+2x-3. Also verify the relationship between the ze

Finger [1]

Solution:

we have been asked to verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial $4x^3+20x^2+2x-3$

To verify that whether the given values are zeros or not we will substitute the values in the given Polynomial, if it will returns zero, it mean that value is Zero of the polynomial. But if it return any thing other than zeros it mean that value is not the zero of the polynomial.

Let $f(x)=4x^3+20x^2+2x-3\\\\\text{when x=-5}\\\\f(-5)=4(-5)^3+20(-5)^2+2(-5)-3=-13\\\\\text{when x=}\frac{1}{2}\\$

$f( \frac{1}{2} ) = 4 ( \frac{1}{2} )^3+20(\frac{1}{2})^2+2(\frac{1}{2})-3=\frac{7}{2}\\\\$

$\text{when x=}\frac{3}{4}\\\\$

$f( \frac{3}{4} ) = 4 ( \frac{3}{4} )^3+20(\frac{3}{4})^2+2(\frac{3}{4})-3=\frac{183}{16}\\$

Hence -5, 1/2, and 3/4 are not the zeroes of the given Polynomial.

Since sum of roots $=\frac{-b}{a}= \frac{-20}{4}=-5\\$

But $-5+\frac{1}{2}+\frac{3}{4}= \frac{-15}{4}\neq-5$

Hence we do not find any relation between the coefficients and zeros.

Anyway if the given values doesn't represents the zeros then those given values will not have any relation with the coefficients of the p[polynomial.

6 0

2 years ago