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Akimi4 [234]
3 years ago
12

How to solve |x-1|=|x-2| geometrically? ​

Mathematics
2 answers:
Leokris [45]3 years ago
8 0
I don’t quite know about geometrically, but I’m sure this will help.

Algebraically: square both sides, as it negates the modulus(absolute value) brackets.
(x-1)^2=(x-2)^2
x^2-2x+1=x^2-4x+4
The x^2’s cancel out.
-2x+1=-4x+4
2x=3
X=1.5
S_A_V [24]3 years ago
4 0

Answer:

x=3/2 or 1.5

Step-by-step explanation:

Screenshot below should help :)

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I give you points lol
larisa86 [58]

Answer:

yes

Step-by-step explanation:

3 0
3 years ago
EXPERTS PLEASE HELP!!!!!!!!!!!!!!
Arturiano [62]

Answer:

1. D

2. x=65

Step-by-step explanation:

Hi!

Your answer is D because 78 is 120% of x

120% in decimal point is 1.2.

So it's 1.2x is the same as 120% of x

For question 8:

1.2x=78

Isolate x by divide 1.2 on both sides

78/1.2=65

7 0
3 years ago
What's the area of this? PLS HELP
balandron [24]

Answer:

446mm

Step-by-step explanation:

If we box off parts of the area, it makes it easier to solve. I personally broke it into tiny bits:

Upper left box: 16mm

Bigger box (excluding little box): 90mm

Big rectangle: 340mm

Now, add them all together.

Equals 446mm

3 0
3 years ago
Read 2 more answers
Tickets to a baseball game are 20 dollars for an adult and 15 dollars far a student. A school bus tickets for 45 adu6and 600 stu
yulyashka [42]

Answer:The total amount of money that the school will spend for tickets is $9900

Step-by-step explanation:

Tickets to a baseball game are 20 dollars for an adult and 15 dollars for a student. A school bus tickets for 45 adults and 600 students. This means that the total amount spent by the school on adult tickets is 20 × 45 = $900

The total amount spent by the school on students tickets is 15 × 600 = $9000

The total amount of money that the school will spend for tickets will be the sum of the amount spent on adult tickets and student tickets. It becomes

900 + 9000 = $9900

4 0
3 years ago
The total length of pencils A, B and C is 29 cm. Pencil a is 11 cm shorter then pencil B, and pencil B is twice as long a pencil
satela [25.4K]

The length of pencil A is 5 cm

<em><u>Solution:</u></em>

Let the length of pencil A be "x"

Let the length of pencil B be "y"

Let the length of pencil C be "z"

<em><u>The total length of pencils A, B and C is 29 cm</u></em>

Therefore,

length of pencil A + length of pencil B + length of pencil C = 29

x + y + z = 29 ------------ eqn 1

<em><u>Pencil A is 11 cm shorter then pencil B</u></em>

x = y - 11 ------- eqn 2

<em><u>Pencil B is twice as long a pencil C</u></em>

y = 2z

z = \frac{y}{2} ------ eqn 3

<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>

y - 11 + y + \frac{y}{2} = 29\\\\2y + \frac{y}{2} = 29 + 11\\\\\frac{4y+y}{2} = 40\\\\5y = 80\\\\y = 16

<em><u>Substitute y = 16 in eqn 2</u></em>

x = 16 - 11

x = 5

Thus length of pencil A is 5 cm

5 0
3 years ago
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