Given:
m∠APB = 19°
To find:
The arc measure of DBC.
Solution:
∠APB and ∠DPC are vertical angles.
By vertical angle theorem:
m∠APB = m∠DPC
m∠DPC = 19°
DB is the diameter of the circle.
Angle measure of diameter = 180°
m∠DPB = 180°
m∠DPC + m∠CPB = m∠DPB
19° + m∠CPB = 180°
Subtract 19° from both sides.
19° + m∠CPB - 19° = 180° - 19°
m∠CPB = 161°
<em>The measure of central angle is equal to the measure of intercepted arc.</em>
m∠CPB = m(ar CPB)
m(ar CPB) = 161°
The arc measure of DBC is 161°.
Answer:
D. 150 cm^2
you add the surface area of each side.
Answer:
Isolate the variable by dividing each side by factors that don't contain the variable.
z = 6
If the picture is your question, the answer is 2 over 3x^3y^2 -1
(The “-1” at the end isn’t with the “^2”, but is with “3y^2”)