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MAXImum [283]
3 years ago
6

Pls help ASAP!!!!!! I will cash app

Mathematics
2 answers:
4vir4ik [10]3 years ago
6 0

Answer:

C

Step-by-step explanation:

Since the weekend rate is a one time payment take it away from 125. leaving you with 75, divide by 8.25 since that is an hourly fee. which equals 9.09

SCORPION-xisa [38]3 years ago
6 0

Answer:

c is corecct

Step-by-step explanation:

You might be interested in
What is 122/11 equivalent to as a decimal??
kipiarov [429]

divide it two numbers to get 11.090909 which would most likely to be 11.10

3 0
3 years ago
PLEASE, I AM DESPERATE! CAN ANYONE, HELP ME WITH MY MATH!
Andru [333]
(6,1)&(5,4)
(7,-3)&(4,-8)
(-8,0)&(1,5)
Basically, you are to find the line that passes through 2 points.
Equation: y2-y1=m(x2-x1)
• x1: 6, x2: 5, y1: 1, y2: 4
(4-1)/(5-6)=m
m=3/-1
m=-3
Hence, m= -3x10^0

• x1: 7, x2: 4, y1: -3, y2: -8
(-8--3)/(4-7)=m
m=(-8+3)/-3
m=-5/-3
m=5/3
m=1.66666667
Hence, m=1.6667x10^0

• x1: -8, x2: 1, y1: 0, y2: 5
(5-0)/(1--8)=m
m=5/(1+8)
m=5/9
m=0.55555556
Hence, m=5.56x10^-1

Hope this helps!



5 0
3 years ago
The fourth-grade class donated 750 bottles of water for a 5K run. After the run, there were 89 bottles left. How many bottles of
densk [106]

Answer:

The runners drank 661 bottles of water.

Step-by-step explanation:

Subtract 661 from 750, and you are left with 89.

4 0
1 year ago
Eight subtracted from four times a number is -120?
Vsevolod [243]
-28 because if you add 8 to -120 you get -112 then divide it by 4 and you got -28
5 0
3 years ago
Read 2 more answers
A metalworker has a metal alloy that is 15% copper and another alloy that is 75% copper. How many kilograms of each alloy should
attashe74 [19]
X - the mass of the first alloy (15%)
y - the mass of the second alloy (75%)

x kg of the first alloy contains 15%x=0.15x=(15/100)x=(3/20)x kg of copper
y kg of the second alloy contains 75%y=0.75y=(75/100)y=(3/4)y kg of copper
90 kg of a 51% copper alloy contains 51%*90=0.51*90=45.9 kg of copper

x+y=90 \\
\frac{3}{20}x+\frac{3}{4}y=45.9 \ \ \ |\times (-\frac{4}{3}) \\ \\
x+y=90 \\
\underline{-\frac{1}{5}x-y=-61.2} \\
x-\frac{1}{5}x=90-61.2 \\
\frac{4}{5}x=28.8 \ \ \ |\times \frac{5}{4} \\
x=36 \\ \\
36+y=90 \\
y=90-36 \\
y=54

The metal worker should combine 36 kg of the 15% copper alloy and 54 kg of the 75% copper alloy to create 90 kilograms of a 51% copper alloy.
7 0
3 years ago
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