What is 8x9-6+7(5-4x8)

What are the steps for using a compass and straightedge to construct a regular hexagon inscribed in a circle?

N76 [4]

The steps to construct a regular hexagon inscribed in a circle using a compass and straightedge are given as follows:

1. Construct a circle with its center at point H.

2. Construct horizontal line l and point H on line l

3. Label the point of intersection of the circle and line l to the left of point H, point J, and label the point of intersection of the circle and line l to the right of point H, point K.

4. Construct a circle with its center at point J and having radius HJ . Construct a circle with its center at point K having radius HJ

5. Label the point of intersection of circles H and J that lies above line l, point M, and the point of their intersection that lies below line l, point N. Label the point of intersection of circles H and K that lies above line l, point O, and the point of their intersection that lies below line l, point P.

6. Construct and JM⎯⎯⎯⎯⎯, MO⎯⎯⎯⎯⎯⎯⎯, OK⎯⎯⎯⎯⎯⎯⎯, KP⎯⎯⎯⎯⎯, PN⎯⎯⎯⎯⎯⎯, and NJ⎯⎯⎯⎯⎯ to complete regular hexagon JMOKPN .

3 0

3 years ago

6x + 5y = 4 - 6x + y = 20

Masja [62]

Answer:

x = -8/3

y = 4

Step-by-step explanation:

I assume you want to solve for x and y.

The best way to do this with the two formulas given is elimination. This means add the two equations together.

6x + 5y = 4

-6x + y = 20

The 6 x and -6x will cancel each other. By adding the like terms of the two together you will come out with

6y = 24

Now solve for y by dividing both sides by the 6.

y = 24/6 = 4

Now that we have y, you can plug it into one of the equations and solve for x.

Let's use -6x + y =20.

So plug in the 4 for y to get -6x + 4 = 20

Subtract the 4 from both sides then solve for y by dividing both sides by the -6.

-6x = 16

x = -16/6

You can reduce that down so that x = -8/3.

5 0

3 years ago

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The subsets of the real numbers can be represented in a Venn diagram as shown. To which subset of real numbers does −2π belong?

Alecsey [184]

Answer:

D

Step-by-step explanation:

Whole numbers are the basic counting numbers: $0,\ 1,\ 2,\ 3,\ 4, \....$

Integers are whole numbers and negative numbers: $...,\ -2,\ -1,\ 0,\ 1,\ 2,\ ...$

Rational numbers are all fractions $\frac{m}{n},$ where m is an integer and n is a natural number.

Irrational numbers are all real numbers that are not rational.

Number $\pi$ is irrational number (it is not counting number, so it is not whole number, not integer number), it cannot be represented as a fraction, so it is not rational number, thus this number is irrational number.