the answer would be 
because you would need to find the LCD, which in this case would be 56 and you solve from there.
Answer:
the answer will be Root 2
Step-by-step explanation:
x^2 = 1^2 + 1^2
We take the unmentioned side as 1 because it is an isosceles triangle and thus 2 of the sides will have the same measure
x^2 = 1 + 1
x^2 = 2
taking square root on both the sides
x = root of 2
Answer:
yes it is
Step-by-step explanation:
F(x) = 18-x^2 is a parabola having vertex at (0, 18) and opening downwards.
g(x) = 2x^2-9 is a parabola having vertex at (0, -9) and opening upwards.
By symmetry, let the x-coordinates of the vertices of rectangle be x and -x => its width is 2x.
Height of the rectangle is y1 + y2, where y1 is the y-coordinate of the vertex on the parabola f and y2 is that of g.
=> Area, A
= 2x (y1 - y2)
= 2x (18 - x^2 - 2x^2 + 9)
= 2x (27 - 3x^2)
= 54x - 6x^3
For area to be maximum, dA/dx = 0 and d²A/dx² < 0
=> 54 - 18x^2 = 0
=> x = √3 (note: x = - √3 gives the x-coordinate of vertex in second and third quadrants)
d²A/dx² = - 36x < 0 for x = √3
=> maximum area
= 54(√3) - 6(√3)^3
= 54√3 - 18√3
= 36√3.
