How can you tell from the equation of a rational function if the function has a hole in the graph ( a removable discontinuity) a
1 answer:
Consider that,
x^2+4x+4 = (x+2)(x+2)
x^2+7x+10 = (x+2)(x+5)
Dividing those expressions leads to
(x^2+4x+4)/(x^2+7x+10) = (x+2)/(x+5)
The intermediate step that happened is that we have (x+2)(x+2) all over (x+2)(x+5), then we have a pair of (x+2) terms cancel as the diagram indicates (see below). This is where the removable discontinuity happens. Specifically when x = -2. Plugging x = -2 into (x+2)/(x+5) produces an output, but it doesn't do the same for the original ratio of quadratics. So we must remove x = -2 from the domain.
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Answer:
The amount is $1346.86 and the interest is $346.86.
Step-by-step explanation:
To start, use the formula A = P(1+)ⁿ°ᵇ [In this case b = time in years]
So, P = $1000, r = 6$, n = 4 and B = 5 years
After plugging it in you get,
A = 1000(1+)⁴°⁵
A = 1000 x 1.015^20
A = 1000 x 1.346855
A = 1346.86
To find the interest, use the formula A= P + I; Since A = 1346.86 and P = 1000 you get:
1346.86 = 1000 + I
I = 1346.86 - 1000
I = 346.86
Then you're finished! Hope this helped!
Brainliest would be appreciated! :)