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Lapatulllka [165]
2 years ago
9

Which expression is equal 2n - 6

Mathematics
1 answer:
mestny [16]2 years ago
6 0

Answer:

-2(n-3)

Step-by-step explanation:

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labwork [276]

Answer:

wdym get rid of the "stupld"

Step-by-step explanation:

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3 years ago
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Convert each fraction to a decimal then a percent 4/25 3/11
sashaice [31]

Answer:

4/25=0.16=16%

3/11=0.27=27%

Step-by-step explanation:

5 0
3 years ago
2x + 7= -11 please help
Dvinal [7]

Answer:

x = -9

Step-by-step explanation:

You are solving for x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 7 from both sides:

2x + 7 (-7) = -11 (-7)

2x = -11 - 7

2x = -18

Next, divide 2 from both sides:

(2x)/2 = (-18)/2

x = -18/2

x = -9

x = -9 is your answer.

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3 years ago
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Elan Coil [88]

Answer:

<h2>2</h2>

Step-by-step explanation:

\sqrt{4}  = 2 \\ 2 \times 2 = 4

3 0
3 years ago
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A charter airline finds that on its Saturday flights from Philadelphia to London, all 120 seats will be sold if the ticket price
Nataliya [291]

Answer:

a) P=3(120-s)+200

b) 215 \leq P \leq 290

Step-by-step explanation:

For this case we can use a linear model to solve the problem.

s) Create an equation to express the increase on the price tickets and the number of seats sold

s number of seats, if w analyze the info given the number of seats after increase the price is given by 120-s.

And let P the price for the ticket. So after the increase in ticket price the expression for the increase is P-200.

We have an additional info, for each increase of $3 the number of setas decrease 1. And the equation that gives to us the price change in terms of the increase of price is:

P-200=3(120-s)

So then our linear equation is given by:

P=3(120-s)+200

b) Over a certain period, the number of seats sold for this flight ranged between 90 and 115. What was the corresponding range of ticket prices?

So for this case we just need to replace the limits into the linear equation and see what we got:

P_L=3(120-90)+200=290

P_U=3(120-115)+200=215

So the corresponding range of ticket prices is:

215 \leq P \leq 290

4 0
3 years ago
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