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faltersainse [42]
3 years ago
6

Isotope ⁷⁹br has an abundance of 50.69%

Mathematics
1 answer:
Simora [160]3 years ago
5 0

Answer:

79.986

Step-by-step explanation:

Let A represent isotope ⁷⁹Br

Let B represent isotope ⁸¹Br

From the question given above, the following data were obtained:

For Isotope A (⁷⁹Br):

Mass of A = 79

Abundance of A (A%) = 50.69%

For isotope B (⁸¹Br):

Mass of B = 81

Abundance of B (B%) = 49.31%

Relative atomic mass of Br =?

The relative atomic mass (RAM) of Br can be obtained as follow:

RAM = [(Mass of A × A%) /100] + [(Mass of B × B%) /100]

= [(79 × 50.69) /100] + [(81 × 49.31) /100]

= 40.0451 + 39.9411

= 79.986 amu

Thus, the relative atomic mass of Br is 79.986

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Answer:

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Find two positive numbers if their ratio is 8:5 and the difference is 150.
natima [27]
Let's call the two numbers x and y. We can write a system of equations to describe the situation:

5x = 8y

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Let's solve the first equation for x:

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3y/5 = 150

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If y = 250, then x is:

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7 0
3 years ago
What is 9.375 Rounded to the nearest hundredth
stiks02 [169]

Note the hundredth place value (underlined and bolded):

9.3<u>7</u>5

Look at the number to the right of the hundredth place value. It is a 5. Because you round up if the number is 5 or greater, you round up in this case (you round down if it is 4 or less).

9.375 rounded to the nearest hundredth is 9.38

~

3 0
4 years ago
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Kryger [21]

Answer:

x=2

Step-by-step explanation:

The diagram is attached below

  • TW=3
  • CW=x
  • TU=x+7
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TU=TW+WU

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WU=x+4

To determine the value of x, we apply the theorem of intersecting chords.

TW X WU = CW X WV

x(x+4)=6 \times x\\x^2+4x=6x\\x^2=6x-4x\\x^2=2x\\$Divide both sides by x\\x=2

4 0
3 years ago
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