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devlian [24]
2 years ago
10

1 Officials estimate the probability that England will host the World Cup in 2018 is 58%. If the estimate is correct, what is th

e probability that England will not host the World Cup?
2 A weather forecast predicts the probability that it will snow the
following day is 23.
What is the probability that it will not snow the following day?


3 There is a 0.7 chance a tennis player will win her next match.
The probability that she will lose her next match is 0.2.
What is the probability the tennis player will draw her next match?

4 At a college, 160 students study Psychology.
120 of the students are female.
What is the probability a Psychology student chosen at random
will be female?

6 A train company calculates that the probability that a train will break down on any one day is 0.012.
On one particular day, the train company has 650 trains running.
How many trains does the train company estimate will break down that day?​
Mathematics
1 answer:
TiliK225 [7]2 years ago
3 0

Answer:

  1. 42%
  2. 1/23
  3. 1.1

4. 3/4

Step-by-step explanation:

  1. 100%_58%=42%
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Maria throws a softball straight up into the air with an initial velocity of 50 ft/sec. The ball leaves her hand when it is exac
Nataly_w [17]

Answer:

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

Step-by-step explanation:

Let suppose that effects from air friction and Earth's rotation can be neglected, so that the softball can be modelled experiment a free fall, that is, an uniform accelerated motion due to gravity. From we know the initial velocity and position of the position and we can determine the final position of the ball as a function of the final velocity:

v_{f}^{2} = v_{o}^{2}+2\cdot a \cdot (s_{f}-s_{o}) (1)

Where:

s_{o}, s_{f} - Initial and final position of the softball, measured in feet.

a - Acceleration, measured in meters per square second.

v_{o}, v_{f} - Initial and final velocities of the softball, measured in feet per second.

If we know that v_{o} = 50\,\frac{ft}{s}, a = -32.174\,\frac{m}{s^{2}} and s_{o} = 4\,ft, then the equation that models the situation is:

v_{f}^{2} = 2500-64.348\cdot (s_{f}-4)

Then, we clear the final position of the softball:

-\frac{v_{f}^{2}-2500}{-64.348} = s_{f}-4

s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

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2 years ago
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Answer:      -2.5,, -0.9,, -1/3,, 1.7,, 27/4

Step-by-step explanation:

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