It would be 26 repeating itself
Hello here is a solution :
x²-8y-6x+y²=4....(1)
A)
x²-6x = x²-2(3)x+9-9
= x²-2(3)x+3²-9
x²-6x =(x-3)² -9
B)
y²-8y = y²-2(4)y +4²-16
y²-8y = (y-4)²-16
C)
in (1) :
(x-3)² -9 +(y-4)²-16 = 4
(x-3)² +(y-4)² = 29 ...<span>is the standard form of the equation
</span> <span>Select answer 1 :
</span><span>A: 3
B: 4
C: (x−3)2+(y−4)2=29</span>
One vertex the rectangle lies on the straight line x + y = 6, which means that the sum of lengths of two adjacent sides is 6. Then the perimeter is 12 cm.
L + W
length plus width
example: L = 10" W = 20" 10 x 20 = 200
The perfect cubes less than 1000 are:
<span>1^3 = 1 </span>
<span>2^3 = 8 </span>
<span>3^3 = 27 </span>
<span>4^3 = 64 </span>
<span>5^3 = 125 </span>
<span>6^3 = 216 </span>
<span>7^3 = 343 </span>
<span>8^3 = 512 </span>
<span>9^3 = 729
</span>
so
<span>2^3 = 8 could only be 1 + 1, but this is 2, not 8. </span>
<span>3^3 = 27 could be 1 + 1, 1 + 8 or 8 + 8, but all of these are too small </span>
4^3 = 64 could be 1 + 1, 1 + 8, 1 + 27, 8 + 8, 8 + 27, 27 + 27.
<span> general proof that a^3 + b^3 = c^3 holds for no positive integers
</span>hope it helps
