Evaluate the logarithm log(5)1 (5) is base

Mathematics

1 answer:

marta [7]3 years ago

8 0

Answer: 0

log (5) 1
log b n = e
b^e = n
5^x = 1
x = 0
5^0 = 1 (any number to the power of 0 equals 1)

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the diameter of a piston for an automobile is 3 11/16in with tolerence of 1/64in. find the upper and lower limits of the pistons

padilas [110]

Upper Tolerance

Remark

The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.

Solution

Upper Limit

$\dfrac{11}{16} + \dfrac{1}{64}$

Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4

$\dfrac{11*4}{16*4} + \dfrac{1}{64}$

$\dfrac{11*4}{16*4} + \dfrac{1}{64}$ Which results in

$\dfrac{44}{64} + \dfrac{1}{64}$

With a final result for the fractions of 45/64

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Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.

$\dfrac{11}{16} - \dfrac{1}{64}$

Your answer should be 3 and 43/64

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Sedaia [141]

Answer: b

Step-by-step explanation:

NOTE:

Hypothesis: "if" part of the sentence
Conclusion: "then" part of the sentence

hypothesis : If two lines intersect at right angles

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monitta

To find the interquartile range, you will list the data that is presented in the stem and leaf plot.

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Read 2 more answers

What is AB? in the right triangle shown, AC = BC = 2

saul85 [17]

Answer:

2.83

Step-by-step explanation:

using the pythagorean theorem, $AB=\sqrt{AC^2+BC^2}=\sqrt{2^2+2^2}$ ≈ $2.83$