Answer:Jim gets £24
Step-by-step explanation:
Let the amount Natasha gets be represented as x
SO that Krutika getting three times as much as Natasha be represented as 3x
AND Jim getting twice as much as Krutika be represented as 2 x 3x=6x
The equation to show how much each gets can be represented as
x + 3x +6x=40
Solving
x +3x + 6x=40
10x =40
x =40/10 =4
Natasha gets £4
Krutika gets 3x =3x4= £12
Jim gets 6x=6 x4= £24
(a) If
<em>f(x)</em> = <em>a</em>₀ + <em>a</em>₁ <em>x </em>+<em> a</em>₂ <em>x</em> ² + <em>a</em>₃ <em>x</em> ³
then from the given conditions we get the system of equations,
<em>f</em> (-1) = <em>a</em>₀ - <em>a</em>₁<em> </em>+<em> a</em>₂ - <em>a</em>₃ = -1
<em>f</em> (1) = <em>a</em>₀ + <em>a</em>₁<em> </em>+<em> a</em>₂ + <em>a</em>₃ = 2
<em>f</em> (2) = <em>a</em>₀ + 2<em>a</em>₁<em> </em>+ 4<em>a</em>₂ + 8<em>a</em>₃ = 1
<em>f</em> (3) = <em>a</em>₀ + 3<em>a</em>₁<em> </em>+<em> </em>9<em>a</em>₂ + 27<em>x</em> ³ = 5
(b) Similarly, if
<em>f(x)</em> = <em>a</em>₀ + <em>a</em>₁ <em>x </em>+<em> a</em>₂ <em>x</em> ² + <em>a</em>₃ <em>x</em> ³
then
<em>f'(x)</em> = <em>a</em>₁<em> </em>+<em> </em>2<em>a</em>₂ <em>x</em> + 3<em>a</em>₃ <em>x</em> ²
so that the given conditions yield the system,
<em>f</em> (1) = <em>a</em>₀ + <em>a</em>₁<em> </em>+<em> a</em>₂ + <em>a</em>₃ = 0
<em>f'</em> (1) = <em>a</em>₁<em> </em>+<em> </em>2<em>a</em>₂ + 3<em>a</em>₃ = 2
<em>f</em> (2) = <em>a</em>₀ + 2<em>a</em>₁<em> </em>+<em> </em>4<em>a</em>₂ + 27<em>a</em>₃ = 3
<em>f'</em> (2) = <em>a</em>₁<em> </em>+<em> </em>4<em>a</em>₂ + 12<em>a</em>₃ = -1
After solving for both variables, you find that each bus can hold 59 students and each van can hold 18 students.
Step-by-step explanation:
You can find the amount of students each vehicle can carry by representing the two scenarios in equations.
You are trying to find how many students will fit in each bus or van, so the two variables used will be "b" to represent how many students can fit in a bus and "v" to represent how many students can fit in a van.
High school A used 1 van and 6 buses, so there will be 1"v" and 6"b" for 372 students.
High school B used 4 vans and 12 buses, so there will be 4"v" and 12"b" for 780 students.
Now, represent these in equations:

We can use substitution to solve this system:
can be rewritten as
after subtracting 6b from both sides. You can then substitute this new value of "v" into the other equation to solve for "b":

After solving for b, you can then substitute the new value of b into the other equation to find the value of v:

After solving for both variables, you find that each bus can hold 59 students and each van can hold 18 students.
Answer:
if that is supposed be a decimal then round tenths place which is still six
Step-by-step explanation:
First, let's turn all the numbers into improper fractions so that we can find the answer easier.
-2
= r - 
-
= r - 
Now we have to isolate 'r'.
First, we have to make sure that the variable is on one side and all the numbers are on the other side.
To do this, we have to add
to both sides.
In order to do this, we need to ensure that both fractions have a common denominator.
-
= r - 
Ensure that the denominators are the same:
= r - 
+
= r
= r
Good luck!