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3 years ago

How do I round 622 to the nearest ten and hundred?

Mathematics

1 answer:

mafiozo [28]3 years ago

8 0

Round to the Nearest Ten

622

Identify the tens digit: 622
Identify the next smallest place value (the digit to the right of the tens place): 622
Is that digit greater than or equal to five? NO - we round down
The tens digit stays the same. Each digit after becomes a zero.It becomes 620.


Round to the Nearest Hundred

622

Identify the hundreds digit: 622
Identify the next smallest place value (the digit to the right of the hundreds place): 622
Is that digit greater than or equal to five? NO - we round DOWN
The hundreds digit is STAYS THE SAME. Every digit after it becomes a zero.
Its becomes 600.

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Please help i really need an A and i'm horrible at math ):

Dovator [93]

See the attached picture for 2 options for question 1 and 2 depending on how the fractions are written.

Question #3:

17 = -13 - 8x

Add 13 to each side:

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3 years ago

How many solutions does 6 - 3x = 4 - x - 3 - 2x have?

White raven [17]

Answer:

No Solution

Step-by-step explanation:

6 - 3x = 4 - x - 3 - 2x (Given)

6 - 3x = -1 -3x (combine like terms)

7 (addition)

The x cancels each other out so no solution.

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3 years ago

The grocery store sells kumquats for $4.75 a pound and Asian pears for $3.75 a pound. Write an equation in standard form for the

maks197457 [2]

to find the solution to this problem, we must understand that the sum of the amount that the customer could be bought is $12. $4.75 pound of kumquats and Asian pears for $3.75 mean mathematically as $12. $4.75 kumquats + $3.75 Asian, this last sum is equal to $12, so the true answer is the choice B: 4.75k + 3.75p = 12 Hope this helps. Let me know if you need additional help!

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3 years ago

Which of the following is an exponential equation? y = mx + b y = a(b^x)

Darina [25.2K]

Y = a(b^x)

y=mx + b is the equation of a line. It is a linear function because it has a constant rate of change.

y = a(b^x) is an exponential function because it has has an exponent and its rate of change is not constant

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3 years ago

What is the solution for the following equation? x^2-6x+9=11

tankabanditka [31]

Make one side equal zero
minus 11 to both sides
x^2-6x-2=0
another quadratic equation

if you hahve
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

1x^2-6x-2=0
a=1
b=-6
c=-2

x= $\frac{-(-6)+/- \sqrt{(-6)^{2}-4(1)(-2)} }{2(1)}$
x= $\frac{6+/- \sqrt{36+8} }{2}$
x= $\frac{6+/- \sqrt{44} }{2}$
x= $\frac{6+/- 2\sqrt{11} }{2}$
x= $3+/- \sqrt{11}$
x= $3+ \sqrt{11}$ or $3- \sqrt{11}$

aprox
x=6.31662 or -0.316625

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3 years ago