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Mariulka [41]
3 years ago
8

Prove

x+1)^{2}(x+2)=(x^3+3x+21x+1)" alt="(x+1)^{2}(x+2)=(x^3+3x+21x+1)" align="absmiddle" class="latex-formula"> no files
Mathematics
1 answer:
tekilochka [14]3 years ago
6 0

Answer:

LHS ≠ RHS

Step-by-step explanation:

LHS =\\\\=(x+1)^2 (x + 2) \\\\=(x^2 + 2x + 1)(x+2)\\\\=x(x^2 + 2x + 1) + 2(x^2 + 2x + 1) \\\\=(x^3 + 2x^2 + x ) + ( 2x^2 + 4x + 2) \\\\=x^3 + 2x^2 + x + 2x^2 + 4x + 2 \\\\=x^3 + 4x^2 + 5x + 2

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Find the sum of all integers 30 to 80. (Is there a formula to do this?
Shkiper50 [21]

Answer:

Add all the numbers from 30 to 80 and that is your answer

Step-by-step explanation:


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3 years ago
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When a cold drink is taken from a refrigerator, its temperature is 5°C. After 25 minutes in a 20°C room its temperature has incr
Andrews [41]

Answer:

  (a)  13.85 °C

Step-by-step explanation:

The temperature difference is a decaying exponential function of time. Here, it decreases from an initial difference of 15 °C to 10 °C after 25 minutes. So, that temperature difference can be modeled as ...

  ΔT = 15(10/15)^(t/25)

We want to find the value of this at t=55. It is ...

  ΔT = 15(2/3)^(55/25) ≈ 6.15

This is the amount the temperature of the drink is below room temperature.

  drink temperature = (20 - 6.15) °C = 13.85 °C

The temperature of the drink after 55 minutes is about 13.85 °C.

3 0
3 years ago
Find all solutions of the equation: 2cos^2x-cosx=1
Art [367]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/3166243

——————————

Solve the trigonometric equation:

     \mathsf{2\,cos^2\,x-cos\,x=1}\\\\ \mathsf{2\,cos^2\,x-cos\,x-1=0}


Make a substitution:

     \mathsf{cos\,x=t\qquad (-1\le t\le 1)}

and the equation becomes

     \mathsf{2t^2-t-1=0}


Rewrite conveniently  – t  as  + t – 2t,  and then factor the left-hand side by grouping:

      \mathsf{2t^2+t-2t-1=0}\\\\ \mathsf{t\cdot (2t+1)-1\cdot (2t+1)=0}


Factor out  2t + 1:

     \mathsf{(2t+1)\cdot (t-1)=0}\\\\ \begin{array}{rcl} \mathsf{2t+1=0}&~\textsf{ or }~&\mathsf{t-1=0}\\\\ \mathsf{2t=1}&~\textsf{ or }~&\mathsf{t=1}\\\\ \mathsf{t=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{t=1} \end{array}


Substitute back for  t = cos x:

     \begin{array}{rcl}\mathsf{cos\,x=\dfrac{\,1\,}{2}}&~\textsf{ or }~&\mathsf{cos\,x=1}\\\\ \mathsf{cos\,x=cos\,60^\circ}&~\textsf{ or }~&\mathsf{cos\,x=cos\,0} \end{array}


Therefore,

     \begin{array}{rcl} \mathsf{x=\pm\,60^\circ+k\cdot 360^\circ}&~\textsf{ or }~&\mathsf{cos\,x=0+k\cdot 360^\circ} \end{array}

where  k  is an integer.


Solution set:   

\mathsf{S=\left\{x\in\mathbb{R}:~~x=-\,60^\circ+k\cdot 360^\circ~~or~~x=60^\circ+k\cdot 360^\circ~~or~~x=k\cdot 360^\circ,~~k\in\mathbb{Z}\right\}}


I hope this helps. =)

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What is the density of a sample with a mass of 5250g and a volume of 4.5mL?
just olya [345]

Step-by-step explanation:

Density=5250/4.5=1166.66 g/ml

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VashaNatasha [74]
It's B because the car gets older as the years of ownership go up; resulting in a negative correlation on a graph. Hope I helped :)
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3 years ago
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