3 years ago

Help would be good i dont know how to do this

1 answer:

5 0

$\frac{x^2-4x-32}{x^2+7x+12}=\frac{x^2+4x-8x-32}{x^2+4x+3x+12}=\frac{x(x+4)-8(x+4)}{x(x+4)+3(x+4)}=\\\frac{(x+4)(x-8)}{(x+4)(x+3)}=\frac{x-8}{x+3}$

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Stella [2.4K]

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