Question

Help would be good i dont know how to do this

Answer 1

$\frac{x^2-4x-32}{x^2+7x+12}=\frac{x^2+4x-8x-32}{x^2+4x+3x+12}=\frac{x(x+4)-8(x+4)}{x(x+4)+3(x+4)}=\\\frac{(x+4)(x-8)}{(x+4)(x+3)}=\frac{x-8}{x+3}$