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gizmo_the_mogwai [7]
3 years ago
6

I need to know how to find the slope of the line for #2

Mathematics
1 answer:
son4ous [18]3 years ago
3 0
Slope formula : (y2 - y1) / (x2 - x1)
now pick 2 points on ur line...
(1,2)......x1 = 1 and y1 = 2
(3,0)......x2 = 3 and y2 = 0
now sub
slope = (0 - 2) / (3 - 1) = -2/2 = -1 <== ur slope is -1
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How to work -1x-2y=-13 x-2y=11 equation by substitution
Norma-Jean [14]
Well if you're wanting to use substitution, you first have to end up with one term on either side of the equation. Use the second one as it's easiest. 

So: x-2y=11, so find -2y as there is a -2y in the first equation. 
then that becomes -2y=11-x. then sub that into equation 1, and you get:

-x+11-x=-13, which equals to -2x+11=-13, which is -2x=-24, so therefore

x=12. then chuck the x into any of the equations to find what y equals. 

hope this helps!
5 0
3 years ago
2|3x - 2|= 14 how would you solve this absolute value equation?
Feliz [49]

Answer: 2. |3x-2|= 14

|3x-2|=2.7/2

|3x-2|=7

x∈ {3,-5/3

Step-by-step explanation: \frac{5}{3}

6 0
3 years ago
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Find the distance from point A(−9,−3) to the line y = x−6. Round your answer to the nearest tenth.
Vladimir79 [104]

The distance from point A(−9,−3) to the line y = x−6 is 8.5 units

<u>What is slope ?</u>

A line's steepness is determined by its slope. In mathematics, slope is determined by "rise over run" (change in y divided by change in x).

step 1

Find the slope of the perpendicular line to the given line

y=x-6 ---> given line

The slope is m=1

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

m1*m2 = -1

we have

m1=1

substitute

(1)*m2 = -1

so

m2 = -1

step 2

Find the equation of the perpendicular line to the given line

The equation in point slope form is

y-y1=m(x-x1)

we have

m=-1

(x1,y1)=(−9,−3)

substitute

y+3=-1(x+9)--> equation in point slope form

y+3= -x-9

y= -x-12---> equation in slope intercept form

step 3

Find the intersection point between the given line and the perpendicular line to the given line

we have the system of equations

y = x−6.

y= -x-12

Solve the system by graphing

The intersection point is (-3,-9)

see the attached figure

step 4

we know that

The distance between the point A and the point (-3,-9) is the same that the distance between point A and the line y=x-6

the formula to calculate the distance between two points is equal to

d=√[(y2-y1)² + (x2-x1)²]

substitute the values

d=√[(-9+3)² + (-3+9)²]

d= √72 units

simplify

d= 6√2 = 8.5 units

To learn more about the slope from the given link

brainly.com/question/16949303

#SPJ1

8 0
1 year ago
If JM = 5x – 8 and LM = 2x – 6, which expression represents JL?
muminat

Answer:

The expression represents JL is<u> 3x - 2</u>.

Step-by-step explanation:

Given:

JM = 5x – 8 and LM = 2x – 6.

Now, to find expression represents JL.

JM = JL + LM

<em>Subtracting both sides by LM we get:</em>

JM - LM = JL.

JL = JM - LM

Now, putting the expression to get JL:

JL=5x-8-(2x-6)

JL=5x-8-2x+6

JL=3x-2.

Therefore, the expression represents JL is 3x - 2.

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