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kykrilka [37]
3 years ago
5

As an interviewer, it is not necessary to be at eye level with interviewee True False

Computers and Technology
2 answers:
ANTONII [103]3 years ago
7 0

Answer:

True

Hope this helps

Tamiku [17]3 years ago
3 0

Answer:

True

Explanation:

Have a great day

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pickupchik [31]
<span>To give your app users the ability to open your app directly from other apps by clicking a link, you should use:  deep link. With the deep link and its URL functionality, existing app users are driven directly inside the mobile app itself. 
</span>Deep links are usually made up of two parts: a scheme (part of the link that identifies which app to open).<span>and a </span>host and path (<span>the unique location in the app where your content exists).</span>

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3 years ago
What is the name of the function below?<br><br> function go(){<br> alert("hello everybody");<br> }
labwork [276]

Answer:

It’s Java script I think and it makes something say hello everybody

Explanation:

6 0
3 years ago
Monica is teaching herself to paint. What web resource would be the most helpful
strojnjashka [21]

Answer:

Video Tutorial

Explanation:

The others don’t make sense.

3 0
3 years ago
What is the name for the individual sections of the ribbon in PowerPoint 20162
Julli [10]

Answer:

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Explanation:

The ribbon contains the tabs. The tabs contain the command groups which hold commands

IF THIS HELPS PLEASE MARK THIS ANSWER AS BRAINLIEST

6 0
3 years ago
Given the lists list1 and list2, not necessarily of the same length, create a new list consisting of alternating elements of lis
tester [92]

Answer:

The following code is written in Python Programming Language.

Program:

list1=[1,2,3]

 # initialized the list type variable

list2=[4,5,6,7,8]

  # initialized the list type variable

list3=[]

   # initialized the empty list type variable

for j in range(max(len(list1), len(list2))):   #set for loop

 if j<len(list1):

  #set if statement

   list3.append(list1[j])

  #value of list1 appends in list3  

 if j<len(list2):

   #set if statement

   list3.append(list2[j])

  #value of list2 append in list3

print(list3)    #print the list of list3

Output:

[1, 4, 2, 5, 3, 6, 7, 8]

Explanation:

Here, we define three list type variables "list1", "list2", "list3" and we assign value in only first two variables "list1" to [1, 2, 3] and "list2" to [4, 5, 6, 7, 8] and third list is empty.

Then, we set the for loop and pass the condition inside it we pass two if conditions, in first one we compare the list1 from variable "j" inside it the value in list1 will append in list3, and in second one we compare "j" with list two and follow the same process.

After all, we print the list of the variable "list3".

5 0
3 years ago
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