Using the Insert tab, you can convert text into a table and a table into text.

Rebecca has finished with the research and outline portion of her slide presentation now the next logical step is to begin worki

e-lub [12.9K]

Answer:

The answer is creating and layout and template style

Explanation:

APEX VERIFIED just did it

4 0

2 years ago

Read 2 more answers

Write a method that accepts a String object as an argument and returns a copy of the string with the first character of each sen

emmainna [20.7K]

Answer:

The programming language is not stated; However, the program written in C++ is as follows: (See Attachment)

#include<iostream>

using namespace std;

string capt(string result)

{

result[0] = toupper(result[0]);

for(int i =0;i<result.length();i++){

if(result[i]=='.' || result[i]=='?' ||result[i]=='!') {

if(result[i+1]==' ') {

result[i+2] = toupper(result[i+2]);

}

if(result[i+2]==' ') {

result[i+3] = toupper(result[i+3]);

}

} }

return result;

}

int main(){

string sentence;

getline(cin,sentence);

cout<<capt(sentence);

return 0;

}

Explanation:

The method to capitalize first letters of string starts here

string capt(string result){

This line capitalizes the first letter of the sentence

result[0] = toupper(result[0]);

This iteration iterates through each letter of the input sentence

for(int i =0;i<result.length();i++){

This checks if the current character is a period (.), a question mark (?) or an exclamation mark (!)

if(result[i]=='.' || result[i]=='?' ||result[i]=='!') {

if(result[i+1]==' '){ ->This condition checks if the sentence is single spaced

result[i+2] = toupper(result[i+2]);

-> If both conditions are satisfied, a sentence is detected and the first letter is capitalized

}

if(result[i+2]==' '){ ->This condition checks if the sentence is double spaced

result[i+3] = toupper(result[i+3]);

-> If both conditions are satisfied, a sentence is detected and the first letter is capitalized

}

} The iteration ends here

return result; ->The new string is returned here.

}

The main method starts here

int main(){

This declares a string variable named sentence

string sentence;

This gets the user input

getline(cin,sentence);

This passes the input string to the method defined above

cout<<capt(sentence);

return 0;

}

Download cpp

7 0

3 years ago

A common fallacy is to use MIPS (millions of instructions per second) to compare the performance of two different processors, an

yulyashka [42]

The question is incomplete. It can be found in search engines. However, kindly find the complete question below:

Question

Cites as a pitfall the utilization of a subset of the performance equation as a performance metric. To illustrate this, consider the following two processors. P1 has a clock rate of 4 GHz, average CPI of 0.9, and requires the execution of 5.0E9 instructions. P2 has a clock rate of 3 GHz, an average CPI of 0.75, and requires the execution of 1.0E9 instructions. 1. One usual fallacy is to consider the computer with the largest clock rate as having the largest performance. Check if this is true for P1 and P2. 2. Another fallacy is to consider that the processor executing the largest number of instructions will need a larger CPU time. Considering that processor P1 is executing a sequence of 1.0E9 instructions and that the CPI of processors P1 and P2 do not change, determine the number of instructions that P2 can execute in the same time that P1 needs to execute 1.0E9 instructions. 3. A common fallacy is to use MIPS (millions of instructions per second) to compare the performance of two different processors, and consider that the processor with the largest MIPS has the largest performance. Check if this is true for P1 and P2. 4. Another common performance figure is MFLOPS (millions of floating-point operations per second), defined as MFLOPS = No. FP operations / (execution time x 1E6) but this figure has the same problems as MIPS. Assume that 40% of the instructions executed on both P1 and P2 are floating-point instructions. Find the MFLOPS figures for the programs.

Answer:

(1) We will use the formula:

CPU time = number of instructions x CPI / Clock rate

So, using the 1 Ghz = 10⁹ Hz, we get that

CPU time₁ = 5 x 10⁹ x 0.9 / 4 Gh

= 4.5 x 10⁹ / 4 x 10⁹Hz = 1.125 s

and,

CPU time₂ = 1 x 10⁹ x 0.75 / 3 Ghz

= 0.75 x 10⁹ / 3 x 10⁹ Hz = 0.25 s

So, P2 is actually a lot faster than P1 since CPU₂ is less than CPU₁

(2)

Find the CPU time of P1 using (*)

CPU time₁ = 10⁹ x 0.9 / 4 Ghz

= 0.9 x 10⁹ / 4 x 10⁹ Hz = 0.225 s

So, we need to find the number of instructions₂ such that CPU time₂ = 0.225 s. This means that using (*) along with clock rate₂ = 3 Ghz and CPI₂ = 0.75

Therefore, numbers of instruction₂ x 0.75 / 3 Ghz = 0.225 s

Hence, numbers of instructions₂ = 0.225 x 3 x 10⁹ / 0.75 = 9 x 10⁸

So, P1 can process more instructions than P2 in the same period of time.

(3)

We recall that:

MIPS = Clock rate / CPI X 10⁶

So, MIPS₁ = 4GHZ / 0.9 X 10⁶ = 4 X 10⁹HZ / 0.9 X 10⁶ = 4444

MIPS₂ = 3GHZ / 0.75 X 10⁶ = 3 x 10⁹ / 0.75 X 10⁶ = 4000

So, P1 has the bigger MIPS

(4)

We now recall that:

MFLOPS = FLOPS Instructions / time x 10⁶

= 0.4 x instructions / time x 10⁶ = 0.4 MIPS

Therefore,

MFLOPS₁ = 1777.6

MFLOPS₂ = 1600

Again, P1 has the bigger MFLOPS

3 0

2 years ago

How can a Word user insert a page break into a document to isolate a table on a new page?

ki77a [65]

Answer: hit control key and enter key at the same time.

Explanation:

on the keyboard hold down the control key and enter key.

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2 years ago

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You are writing a report about a trip you made to several cities last month. Which of the following paragraph styles would be th

AlekseyPX

I would say B would be the best answer choice out of the given choices

4 0

2 years ago