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3 years ago

What are the x- and y-intercepts of the line 6x−y=10?

Mathematics

1 answer:

Lana71 [14]3 years ago

7 0

Answer:

x= (5/3 , 0)

y= (0 , -10)

Step-by-step explanation:

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Find the value of x. Round to the nearest tenth.! PLEASE HELPP I’ve been stuck on it for HOURS!

barxatty [35]

Answer

63.2 degrees

Step-by-step explanation:

Using law of cosines: 19^2=8^2+14^2-2(8)(14) cos (x)

361=64+196-224 cos(x)

361=260-224cos(x)

101=224cos(x)

divide both sides by 224, which gets you (rounded to 4th decimal place) 0.4509. do inverse cos which gets you 63.2

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3 years ago

Write an equation for the line parallel to the given line that contains C.<br> C(2,8); y = - 4x + 3

Luba_88 [7]

Answer: i love brinly its the best

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Step-by-step explanation:

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3 0

3 years ago

How much is 2+(95X5)

charle [14.2K]

PEMDAS
Parentheses Exponent Multiplication Division Addition Subtraction
Do the math inside parentheses first
95 x 5 = 475
Now, take away the parentheses
2 + 475 = 477
The answer is 477

3 0

3 years ago

Read 2 more answers

The value of A is .<br><br><br> The value of B is

astraxan [27]

Scale Factor is just being multiplied to the width and length.

$8 \times 1.25 = a\\ 28 \times 1.25 = b \\ a = 10 \: \: \: \: \: b = 35$

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3 years ago

Read 2 more answers

Optimization Calculus Problem

frosja888 [35]

$\bf \begin{cases}
V_c=\textit{cylinder's volume}\\
V_h=\textit{hemisphere's volume}\\
A_c=\textit{area of the cylinder}\\
A_h=\textit{area of the hemisphere}
\end{cases}
\\\\\\
V_c+V_h=6000\implies (\pi r^2h)+\left( \frac{2\pi r^3}{3} \right)
\\\\\\
6000=\cfrac{3\pi r^2h+2\pi r^3}{3}\implies 18000-2\pi r^3=3\pi r^2h
\\\\\\
\boxed{\cfrac{6000}{\pi r^2}-\cfrac{2r}{3}=h}
\\\\
-------------------------------\\\\$

$\bf A_c=2\pi rh+2\pi r^2\implies A_c=2\pi r\left(\cfrac{6000}{\pi r^2}-\cfrac{2r}{3} \right)+2\pi r^2
\\\\\\
A_c=\cfrac{12000}{r}-\cfrac{4\pi r^2}{3}\impliedby \textit{say it has a cost of 1, so stays the same}\\\\
-------------------------------\\\\
A_h=2\pi r^2\impliedby \textit{has a cost of 8 times the cylinder's}
\\\\\\
A_h=16\pi r^2\\\\
-------------------------------\\\\$

$\bf \textit{total cost is }A_c+A_h
\\\\\\
\cfrac{12000}{r}-\cfrac{4\pi r^2}{3}+16\pi r^2\implies \cfrac{12000}{r}-\cfrac{4\pi r^2}{3}+\cfrac{48\pi r^2}{3}
\\\\\\
\boxed{C(r)=\cfrac{12000}{r}+\cfrac{44\pi r^2}{3}}$

7 0

3 years ago