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Leokris [45]
3 years ago
12

Drag each number to show whether or not it is a solution to the inequality.

Mathematics
1 answer:
WARRIOR [948]3 years ago
4 0

<h3><u>Step-by-step explanation:</u></h3>

A linear inequality is given to us and we need to drag each number to show whether or not it is a

solution to the inequality .The given inequality to us is ,

\bf\implies 4x - 12 \leq 24 \\\\\bf\implies 4x \leq 24+12 \\\\\bf\implies 4x \leq 36 \\\\\bf\implies x \leq \dfrac{36}{4}\\\\\bf\implies x\leq 9\\\\\bf\implies \boxed{\red{\bf x \in [9,-\infty )  }}

Hence , x can have all values less than or equal to 9. That is x E [ 9 , -∞ ) .

Options provided to us are ,

  • 10
  • 6
  • 9
  • (-5)
  • 12.5
  • 0

Hence values less than or equal to 9 are 9 , 6 , (-5) and 0 .

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Solve to find x and y in the diagram.
lesantik [10]

15x = 90

   x = 6


5(6) + 12y = 90

30 + 12y = 90

12y = 60

  y = 5

Answer: 3rd option

x =6, y = 5

5 0
4 years ago
A sample of 900900 computer chips revealed that 49%49% of the chips do not fail in the first 10001000 hours of their use. The co
dedylja [7]

Answer:

The proportion of chips that do not fail in the first 1000 hours of their use is 52%.

Step-by-step explanation:

The claim made by the company is that 52% of the chips do not fail in the first 1000 hours of their use.

A quality control manager wants to test the claim.

A one-proportion <em>z</em>-test can be used to determine whether the proportion of chips do not fail in the first 1000 hours of their use is 52% or not.

The hypothesis can be defined as:

<em>H₀</em>: The proportion of chips do not fail in the first 1000 hours of their use is 52%, i.e. <em>p</em> = 0.52.

<em>Hₐ</em>: The proportion of chips do not fail in the first 1000 hours of their use is different from 52%, i.e. <em>p</em> ≠ 0.52.

The information provided is:

\hat p=0.49\\n=900\\\alpha =0.02

The test statistic value is:

z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.49-0.52}{\sqrt{\frac{0.52(1-0.52)}{900}}}=-1.80

The test statistic value is -1.80.

Decision rule:

If the <em>p-</em>value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the <em>p</em>-value as follows:

p-value=2\times P(Z

*Use a <em>z</em>-table.

The <em>p</em>-value = 0.07186 > <em>α</em> = 0.02.

The null hypothesis was failed to be rejected at 2% level of significance.

<u>Conclusion</u>:

The proportion of chips that do not fail in the first 1000 hours of their use is 52%.

8 0
3 years ago
The home for sale is listed at $150,000.00. They have $30,000.00 for a down payment and are qualified for a fixed rate 30-year m
klio [65]

Answer:

Estimate: $900.00

Step-by-step explanation:

This cannot be A, B, or C, as it won't make sense with the increase of 75$ each 4 years, with 30K down payment,

3 0
3 years ago
Read 2 more answers
The team ran
juin [17]

The team ran 2 miles.

Step-by-step explanation:

Step 1; The track is \frac{3}{4} miles long and the team ran 2\frac{2}{3} laps on it. To calculate the distance run we multiply the number of laps ran with the distance on each lap.

Distance run = Number of laps × Distance on each lap.

Step 2; We convert 2\frac{2}{3} from a mixed fraction into an improper fraction. To do this, we multiply the whole number with the denominator of the fraction and add with it the numerator of the same fraction whereas the denominator remains unchanged. To convert the fraction 2\frac{2}{3} = ((2 × 3) + 2) / 3 = \frac{8}{3}.

Distance run = Number of laps × Distance on each lap = \frac{8}{3} × \frac{3}{4} = \frac{8}{4} = 2 miles.

3 0
4 years ago
Read 2 more answers
Help me please i'm having alot of trouble
Arte-miy333 [17]

204

71:35=2

2 goes on the top

2x35=70

71-70=1

then carry them down 14

14:35=0

Carry it up it should be 20 up there now

Carry the 0 from the 7140 down to make it 140

140:35=4

Then carry that 4 up and your answer is 204



3 0
3 years ago
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