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2 years ago

Help pls and thank you! :))

Mathematics

2 answers:

alex41 [277]2 years ago

4 0

Answer:

Step-by-step explanation:

4<x because the arrow is going to the right, meaning that the value of x is greater and since the circle is hollow, it is not equal to 4 so that's why is

4<x

babymother [125]2 years ago

3 0

Answer:

4 < x

Step-by-step explanation:

Open circle = < and >

Closed Circle = ≤ and ≥

X is greater than 4 because it is going to the right

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What is the average of -30 -15 -20 55

defon

Answer:

-2.5

Step-by-step explanation:

-30 + (-15) + (-20) + 55 = -10. Then you divide it by how many numbers there are (4). Which equals - 2.5. If this is wrong, then round up to -3.

8 0

2 years ago

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Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li

Sophie [7]

Consider the closed region $V$ bounded simultaneously by the paraboloid and plane, jointly denoted $S$ . By the divergence theorem,

$\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV$

And since we have

$\nabla\cdot\mathbf f(x,y,z)=1$

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

$\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr$
$=\dfrac\pi2$

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by $D$ , we have

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS$

Parameterize $D$ by

$\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k$
$\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k$

which would give a unit normal vector of $\mathbf k$ . However, the divergence theorem requires that the closed surface $S$ be oriented with outward-pointing normal vectors, which means we should instead use $\mathbf s_v\times\mathbf s_u=-u\,\mathbf k$ .

Now,

$\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du$
$=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du$
$=-2\pi$

So, the flux over the paraboloid alone is

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2$

6 0

3 years ago

HELP PLEASE! whats the height and base??

ddd [48]

Answer: 7.5

Step-by-step explanation:

Area of the bottom left triangle = 4x3/2 = 6

Bottom right = 6x3/2 = 9

Top right = 3x4/2 = 6

Top left = 6x3/2 = 9

6+9+6+9 = 30

Each square unit is 4

So the answer should be 30/4 = 7.5

Hope this is correct

8 0

1 year ago

Fraction that is equivalent to but different from 4/13

dem82 [27]

Answer:

8/26

Step-by-step explanation:

All you have to do is multiply the numerator and denominator with the same number. For example, I did 2. 4x2=8, and 2x13=26.

4 0

2 years ago

The table of values represents a quadratic function.

KengaRu [80]

Answer:

-19

Step-by-step explanation:

It's -19 I took the test

Proof in the picture below

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2 years ago

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