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A farmer sells 8.5 kilograms of apples and pears at the farmer's market. 4 5 of this weight is apples, and the rest is pears. Ho

slavikrds [6]

Answer:

your answer gonna be $13 dollars

6 0

3 years ago

Ten young adults living in California rated the taste of a newly developed sushi pizza topped with tuna, rice, and kelp on a sca

timurjin [86]

Answer: For California: μ = 33.1; σ² = 1120.50; Range = 32;

For Iowa: μ = 24.5; σ² = 32.73; Range = 19

Step-by-step explanation:

Mean is the average of a population or a sample. It is defined as

μ = ∑x / n, where

x is each number of the set;

n is the total individuals in the sample.

Calculating the Mean for sample of taste of pizza in California:

μ₁ = $\frac{34+39+40+46+33+31+34+14+15+45}{10}$ = 33.1

Calculating the Mean for the sample in Iowa:

μ₂ = $\frac{28+25+35+16+25+29+24+26+17+20}{10}$ = 24.5

Variance measures how far the number in the set is from the mean. Its formula is

σ² = (∑x-μ)² / n -1

which means to find the variance, you have to get the difference between the number and the mean, square the result, add all of them and then divide by (n-1) individuals.

The Variance for the sample in California is

σ² = $\frac{(34 - 33.1)^{2}+(39-33.1)^{2}+(40-33.1)^{2}+(46-33.1)^{2}+(33-33.1)^{2}+(34-33.1)^{2}+(14-33.1)^{2}+(15-33.1)^{2}+(45-33.1)^{2}}{9}$ σ² = 120.50

The Variance for the sample in Iowa is

σ² = 32.73

Range is the difference between the highest and the lowest number of the set: range = highest - lowest

For the sample in California, the Range is

range = 46 - 14 = 32

For the sample in Iowa:

range = 35 - 16 = 19

For California:

Mean = 33.1;
Variance = 120.50;
Range = 32;

For Iowa:

Mean = 24.5;
Variance = 32.73;
Range = 19;

6 0

3 years ago

H(x)=x-1 is a factor of f(x)=x^5+1. Please select the best answer from the choices provided.

Zanzabum

Answer:true

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If x^2y-3x=y^3-3, then at the point (-1,2), (dy/dx)?

zavuch27 [327]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2866883

_______________

 dy
Find —— for an implicit function:
 dx

x²y – 3x = y³ – 3

First, differentiate implicitly both sides with respect to x. Keep in mind that y is not just a variable, but it is also a function of x, so you have to use the chain rule there:

$\mathsf{\dfrac{d}{dx}(x^2 y-3x)=\dfrac{d}{dx}(y^3-3)}\\\\\\
\mathsf{\dfrac{d}{dx}(x^2 y)-3\,\dfrac{d}{dx}(x)=\dfrac{d}{dx}(y^3)-\dfrac{d}{dx}(3)}$

Applying the product rule for the first term at the left-hand side:

$\mathsf{\left[\dfrac{d}{dx}(x^2)\cdot y+x^2\cdot \dfrac{d}{dx}(y)\right]-3\cdot 1=3y^2\cdot \dfrac{dy}{dx}-0}\\\\\\
\mathsf{\left[2x\cdot y+x^2\cdot \dfrac{dy}{dx}\right]-3=3y^2\cdot \dfrac{dy}{dx}}$

 dy
Now, isolate —— in the equation above:
 dx

$\mathsf{2xy+x^2\cdot \dfrac{dy}{dx}-3=3y^2\cdot \dfrac{dy}{dx}}\\\\\\
\mathsf{2xy+x^2\cdot \dfrac{dy}{dx}-3-3y^2\cdot \dfrac{dy}{dx}=0}\\\\\\
\mathsf{x^2\cdot \dfrac{dy}{dx}-3y^2\cdot \dfrac{dy}{dx}=-\,2xy+3}\\\\\\
\mathsf{(x^2-3y^2)\cdot \dfrac{dy}{dx}=-\,2xy+3}$

$\mathsf{\dfrac{dy}{dx}=\dfrac{-\,2xy+3}{x^2-3y^2}\qquad\quad for~~x^2-3y^2\ne 0}$

Compute the derivative value at the point (– 1, 2):

x = – 1 and y = 2

$\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{-\,2\cdot (-1)\cdot 2+3}{(-1)^2-3\cdot 2^2}}\\\\\\
\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{4+3}{1-12}}\\\\\\
\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{7}{-11}}\\\\\\\\ \therefore~~\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=-\,\dfrac{7}{11}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: implicit function derivative implicit differentiation chain product rule differential integral calculus

6 0

3 years ago

HELP PLEASE HELP AND HURRY

VikaD [51]

Answer:

Alguien me ayudaaa por faa

6 0

3 years ago