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adell [148]
3 years ago
8

Which angle(s) is/are supplementary?

Mathematics
1 answer:
tatiyna3 years ago
4 0

Answer:

Two Angles that add up to 180

Step-by-step explanation:

90 degrees+ 90 degrees= 180 degrees

160degrees+ 20 degrees= 180 degrees

Hope this helps!

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Find the equation of the straight line that passes through the point (1,1/2) and has slope 1/2. Enter the equation in the point-
Nataliya [291]
\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ 1}}\quad ,&{{ \frac{1}{2}}})\quad 
%   (c,d)

\end{array}
\\\quad \\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies\cfrac{1}{2}
\\ \quad \\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad 
\begin{array}{llll}
\textit{plug in the values}\\

\end{array}\\
\qquad \uparrow\\
\textit{point-slope form}
5 0
3 years ago
What is the value of x?<br> Enter your answer in the box
klasskru [66]

Answer:

x is the number you have to multiply by the given number to get the whole value

Step-by-step explanation:

5x*7 x=35

6 0
4 years ago
Mae has a number cube with 6 sides that are numbered 1 through 6. What is the probability that Mae will roll an odd number?
Stels [109]

Answer:

C) P(E)  = \frac{3}{6}<u></u>

The probability that Mae will roll an odd number

<u></u>P(E)  = \frac{3}{6}<u></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that Mae has a number cube with 6 sides that are numbered 1 through 6.</em>

<em>n(S) = { 1,2,3,4,5,6,} = 6</em>

<em>Let 'E ' be the event of odd numbers</em>

<em>Mae will roll an odd number</em>

<em>n(E) = {1, 3, 5} = 3</em>

<u>Step(ii):-</u>

<u>The probability that Mae will roll an odd number</u>

<u></u>P(E) = \frac{n(E)}{n(S)} = \frac{3}{6}<u></u>

<u></u>P(E)  = \frac{3}{6}<u></u>

4 0
3 years ago
Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin
sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x

7 0
3 years ago
Someone help me asappppp!!! Will mark brainliest if right hurry!!!!!!
Readme [11.4K]
They are similar AEB and BDC?
5 0
3 years ago
Read 2 more answers
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