Margin of error, e = Z*SD/Sqrt (N), where N = Sample population
Assuming a 95% confidence interval and substituting all the values;
At 95% confidence, Z = 1.96
Therefore,
0.23 = 1.96*1.9/Sqrt (N)
Sqrt (N) = 1.96*1.9/0.23
N = (1.96*1.9/0.23)^2 = 262.16 ≈ 263
Minimum sample size required is 263 students.
Answer:
Step-by-step explanation:
x 6 =
So all you have to do to find out how much she had before is add up both value 12.50+34.25= 46.75$ (answer)
because y-12.50=34.25 so you would have to had the 12.5 to the other side to find the value of Y
Answer:
Matt's team
Step-by-step explanation:
Sarah's team finished in 1 hour and 30 min
Matt's team finished in 1 hour and 15 min
One third of 27 is 9, which would mean you would just divide 9 over 48.
