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3 years ago

A corporation is a business that:

Business

1 answer:

dimaraw [331]3 years ago

4 0

Answer:

is probably run by a group of two or more owners

Other part of question attached

Answer and Explanation:

Answer and explanation attached

3 0

3 years ago

Select the correct answer.

enot [183]

Answer:

Od Home Page

i selected

7 0

3 years ago

Read 2 more answers

Student tuition at Boehring University is $150 per semester credit hour. The state supplements school revenue by $80 per semes

Butoxors [25]

Answer:

Explanation:

Revenue is $150 per semester credit hour

Materials cost = $21*45=$945

Labor cost = $4500

Overhead cost = $27,000

Total cost=$945+$4500+$27,000=$32,445

Multifactor probability = Revenue/Total cost = (150+80)*45/32,445=10,350/32,445 = 0.32

8 0

4 years ago

Rhubarb pie is a dessert. therefore, whoever eats rhubarb pie eats a dessert

miskamm [114]

The argument above is a deductive reasoning. A deductive reasoning draws a conclusion from a series of premises that are held to be true. The argument also employs no informal fallacy. The confusion lies though on the first premise if it is true.

5 0

3 years ago

You can insure a $42,000 diamond for its total value by paying a premium of D dollars. If the probability of loss in a given yea

ella [17]

Answer:

$E(X) =\sum_{i=1}^n X_i P(X_i)$

Replacing the values that we have:

$1 = 0.98*a + 0.02(a-42) = 0.98a +0.02a -0.84$

And solving for a we got:

$1.84 = a$

So then the premium value for the insurance on this case should be 1840 dollars.

Explanation:

For this case we can define the random variable X as the gain ( in thousand of dollars) of insurance company

We assume that the premium clase charge and amount of a to the company and we know from the info given that:

$p(X=a) = 1-0.02 = 0.98$

$p(X = a-42) = 0.02$

$E(X) = 1$ represent the expected gain in thousand of dollars

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

And using the definition for a discrete random variable we know that :

$E(X) =\sum_{i=1}^n X_i P(X_i)$

Replacing the values that we have:

$1 = 0.98*a + 0.02(a-42) = 0.98a +0.02a -0.84$

And solving for a we got:

$1.84 = a$

So then the premium value for the insurance on this case should be 1840 dollars.

5 0

4 years ago