Set up a system of equations.
0.10d + 0.25q = 39.25
d + q = 250
Where 'd' represents the number of dimes, and 'q' represents the number of quarters.
d + q = 250
Subtract 'q' to both sides:
d = -q + 250
Plug in '-q + 250' for 'd' in the 1st equation:
0.10(-q + 250) + 0.25q = 39.25
Distribute 0.10:
-0.10q + 25 + 0.25q = 39.25
Combine like terms:
0.15q + 25 = 39.25
Subtract 25 to both sides:
0.15q = 14.25
Divide 0.15 to both sides:
q = 95
Now plug this into any of the two equations to find 'd':
d + q = 250
d + 95 = 250
Subtract 95 to both sides:
d = 155
So there are 95 quarters and 155 dimes.
The answer is 10
This is because both points have the same x value, which is 2, which means the distance between them is a straight line. That means that we can simply find the distance between the y values, and -4 to 0 is 4 units, and 0 to 6 is 6 units, so 4 + 6 = 10.
I hope this helps!
79.50 x .06 = 4.77
79.50 + 4.77 = $84.27
The total cost was $84.27
A value that "lies outside" (is much smaller or larger than) most of the other values in a set of data.
For example in the scores 25,29,3,32,85,33,27,28 both 3 and 85 are "outliers".
Cos(θ) = -20/√((-20)^2 +(-21)^2)
.. = -20/-√841 . . . . . . . . . . . . . . . . . θ is a 4th-quadrant angle, so cos(θ) > 0
.. = 20/29
The value of the cosine is 20/29.
