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Rom4ik [11]
3 years ago
10

If

Mathematics
1 answer:
nata0808 [166]3 years ago
6 0

Answer:

you need to repost your question bcos it's not understandable

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Help please?????????
mezya [45]

Answer:

the answer is B i think

Step-by-step explanation:

8 0
3 years ago
teachers for several classes and a district are told to use a new method for teaching reading while all the other classes use tr
OLEGan [10]
The <u>correct answer</u> is:

Experiment

Explanation:

In an experiment, one group is given a treatment while at least one other group is not.  After the treatment is finished, the results of the group that receive the treatment are compared with the results of the group (or groups) that do not receive the treatment, to determine if the treatment had any effect on the group.

In this problem, the different groups are the classes.  Some classes use the new method, which is the treatment, while other classes do not.  At the end of the year, the reading results of each class are compared to see if the treatment (new method) had any effect.
3 0
3 years ago
Read 2 more answers
Which value, in order, will complete the table? ​
tia_tia [17]
Answer: The answer is the first choice.

Explanation:

Because you must find the sin of the x values in the table.

Sin(7pi/6) = -1/2

Sin(5pi/4) = -sqrt 2/2

Sin(4pi/3) = -sqrt 3/2
4 0
3 years ago
A bag contains 4 red balls, 2 green balls, 3 yellow balls, and 5 blue balls. Find each probability for randomly removing balls w
AfilCa [17]

Answer:

\frac{15}{4802}, \frac{15}{9604}, \frac{9}{2401}, \frac{9}{4802}

Step-by-step explanation:

The bag has a total of (4+2+3+5) = 14 balls. Set up the proportions:

Red: \frac{4}{14}

green: \frac{2}{14}

yellow: \frac{3}{14}

blue: \frac{5}{14}

Now solve!

Removing 1 yellow, 1 red, 1 green, and 1 blue = \frac{3}{14} \cdot \frac{4}{14}  \cdot \frac{2}{14}  \cdot \frac{5}{14} =\frac{15}{4802}

Removing 1 blue, 1 green, 1 green, and 1 yellow = \frac{5}{14} \cdot \frac{2}{14}  \cdot \frac{2}{14}  \cdot \frac{3}{14} =\frac{15}{9604}

Removing 1 red, 1 red, 1 yellow, and 1 yellow = \frac{4}{14} \cdot \frac{4}{14}  \cdot \frac{3}{14}  \cdot \frac{3}{14} =\frac{9}{2401}

Removing 1 green, 1 yellow, 1 yellow, and 1 red = \frac{2}{14} \cdot \frac{3}{14}  \cdot \frac{3}{14}  \cdot \frac{4}{14} =\frac{9}{4802}

4 0
2 years ago
Write the relation as a set of ordered pairs.
ankoles [38]

Answer:

option B is the answer.

7 0
3 years ago
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