Ask question

Ask question

All categories

4 years ago

7

Please help me out!!!!!

1 answer:

dangina [55]4 years ago

5 0

<h3>Solution:</h3>

Inverse of ${12}^{2}$ is ${12}^{ \frac{1}{2} }$

<h3>Explanation:</h3>

Because ${12}^{ \frac{1}{2} } = \sqrt[2]{12}$ Which is the inverse of ${12}^{2}$

<h2>Answer:</h2>

Option C. Is the correct answer.

You might be interested in

A store owner purchases thirty 75-watt light bulbs and 40 fluorescent light bulbs for a total cost of $95. A second purchase, at

N76 [4]

Answer: 75-watt are 30$ fluorescent are 30$ in the second and 65$ in the first

Step-by-step explanation: i calculated thirty 75-watt and the fluorescent and got these kinda hard to explain hope i helped:)

7 0

3 years ago

Find the area of the triangle below.<br>Be sure to include the correct unit in your answer.<br><br>

OleMash [197]

Answer:

area of triangle= 1/2*h*b

= 1/2*6*16

=3*16

= 48 yd²

This is your answer. If I'm right so,

Please mark me as brainliest. thanks!!!

5 0

3 years ago

Compare the function

krek1111 [17]

They all have the same y-intercept

8 0

3 years ago

Let f(x)=x. The graph of f(x) is transformed into the graph of g(x) by a vertical stretch of 4 units and a translation of 4 uni

Mrac [35]

Answer:

$g(x) = 4x + 4$

Step-by-step explanation:

The given function is f(x)=x.

If we stretch vertically by a factor of 4 and a translation of 4 units up then the new function becomes

$g(x) = 4f(x) + 4$

But f(x)=x

We substitute to obtain the equation of g(x) as

$g(x) = 4x + 4$

8 0

3 years ago

Read 2 more answers

Write an equation of the line satisfying the given conditions. Through (2, -5), parallel to 5x 6y + 7

mojhsa [17]

We have to determine the equation of the line passing through the point (2,-5) and parallel to the line $5x = 6y+7$

When two lines are parallel, then the slopes of the two lines are equal.

Equation of line with point $(x_1, y_1)$ and slope 'm' is given by:

$(y-y_1) = m(x-x_1)$

Since, we have to determine the equation of a line with point (2,-5).

So, the equation of the line is : $(y-(-5)) = m(x-2)$

$y+5 = m(x-2)$

Since, the line is parallel to the line $5x = 6y+ 7$

So, $6y +7 = 5x$

$6y = 5x - 7$

$y = \frac{5}{6}x - \frac{7}{6}$

So, slope of the line 'm' is $\frac{5}{6}$ .

Therefore, the equation of the line is:

$(y+5) = \frac{5}{6}(x-2)$

$6y + 30 = 5x - 10$

$6y - 5x = -10-30$

$6y - 5x = -40$

Therefore, $6y - 5x = -40$ is the required equation of the line.

8 0

3 years ago