Can someone help me with this question??
1 answer:
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Answer:
1) Null hypothesis:
Alternative hypothesis:
2) The One-Sample Proportion Test is used to assess whether a population proportion is significantly different from a hypothesized value
.
3)
And the rejection zone would be
4) Calculate the statistic
5) Statistical decision
For this case our calculated value is on the rejection zone, so we have enough evidence to reject the null hypothesis at 5% of significance and we can conclude that the true proportion is higher than 0.15
Step-by-step explanation:
Data given and notation
n=150 represent the random sample taken
X=21 represent the boys overweight
estimated proportion of boy overweigth
is the value that we want to test
represent the significance level
Confidence=95% or 0.95
z would represent the statistic (variable of interest)
represent the p value (variable of interest)
1) Concepts and formulas to use
We need to conduct a hypothesis in order to test the true proportion of boys obese is higher than 0.15.:
Null hypothesis:
Alternative hypothesis:
When we conduct a proportion test we need to use the z statistic, and the is given by:
(1)
2) The One-Sample Proportion Test is used to assess whether a population proportion is significantly different from a hypothesized value
.
3) Decision rule
For this case we need a value on the normal standard distribution who accumulates 0.05 of the area on the right tail and on this case this value is:
And the rejection zone would be
4) Calculate the statistic
Since we have all the info requires we can replace in formula (1) like this:
5) Statistical decision
For this case our calculated value is on the rejection zone, so we have enough evidence to reject the null hypothesis at 5% of significance and we can conclude that the true proportion is higher than 0.15
Answer:
a:
Step-by-step explanation:
Expand:
Subtract: