Question

A cyclist travelled 32 kilometers for both the 1st and 2nd hours. He took a 30 minute break to eat his lunch. He then travelled 15 kilometers for the final 3rd hour. What is the cyclist's average speed?

Answer 1

Answer:

The cyclist's average speed is 13.43 $\frac{km}{h}$

Explanation:

Speed ​​is a quantity that expresses the relationship between the space traveled by an object and the time used for it. That is, speed is the magnitude that expresses the variation in position of an object and as a function of time, which would be the same as saying that it is the distance traveled by an object in the unit of time.

Average speed relates the change in position to the time taken to effect that change:

$speed=\frac{change in position}{time} =\frac{distance}{time}$

In this case:

• total distance traveled= 32 km + 15 km= 47 km
• total time=  3 hours that the cyclist travels + 30 minutes of rest = 3 hours + 0.5 hours (being 60 minutes equal to 1 hour, then 30 minutes equals 0.5 hours) = 3.5 hours

Replacing:

$speed=\frac{47 km}{3.5 h}$

and solving, you get:

speed= 13.43 $\frac{km}{h}$

The cyclist's average speed is 13.43 $\frac{km}{h}$