Answer:
1/18
Explanation:
The number of ways in which two die can be thrown is the sample space of the experiment
(1,1), (1,2) (1,3), (1,4) (1,5) (1,6)
(2,1), (2,2) (2,3), (2,4) (2,5) (2,6)
(3,1), (3,2) (3,3), (3,4) (3,5) (3,6)
(4,1), (4,2) (4,3), (4,4) (4,5) (4,6)
(5,1), (5,2) (5,3), (5,4) (5,5) (5,6)
(6,1), (6,2) (6,3), (6,4) (6,5) (6,6)
From here it can be seen that there are only two cases where the sum on the two die is 11 i.e., (6,5) and (5,6)
∴ Probability of getting 11 is<u> 1/18</u>