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tekilochka [14]
3 years ago
11

Expand and simplify (×+3)(×-2)​

Mathematics
2 answers:
Neporo4naja [7]3 years ago
4 0

Answer:

x^2 +x -6

11 \frac{3}{10}

\frac{77}{6}

Step-by-step explanation:

r-ruslan [8.4K]3 years ago
3 0

Answer:

multiplyeach values on both sides

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Answer:adsfsaffkfhsadfs

Step-by-step explanation:

I need point sorry im doing a compeition

3 0
2 years ago
Mike and Julie surveyed students to determine how many had a grade of A in math. They recorded their findings for each survey in
grin007 [14]

20/4 = 5

40/8 = 5

60/12 = 5

80/16 = 5


Answer is 5

6 0
2 years ago
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10% commission. what is her commission on a house that she sold for $619,100? round your answer to the nearest cent, if necessar
Svetllana [295]

Answer:

$681

Step-by-step explanation:

619.100 * 10% = 61.91

619.100 + 61.91 = 681.01

Rounding it down because it is not over 5. $681

Therefore your answer will be $681

Hope this helps!

7 0
3 years ago
The function f(x) = 2x2 + 6x - 12 has a domain consisting of the integers from -2 to 1, inclusive. Which set represents the corr
Dimas [21]

Answer:

[-16,-4]

Step-by-step explanation:

We are given that

f(x)=2x^2+6x-12

Domain=[-2,1]

We have to find the set of range values of f(x).

Substitute x=-2

f(-2)=2(-2)^2+6(-2)-12

f(-2)=-16

Substitute x=1

f(1)=2(1)+6(1)-12=-4

Range of f(x)=[-16,-4]

Hence, the set of range values of f(x)

[-16,-4]

7 0
3 years ago
Machine A produces bolts at a uniform rate of 120 every 40 seconds, and Machine B produces bolts at a uniform rate of 100 every
Nutka1998 [239]

Answer:

25 seconds

Step-by-step explanation:

Hi there!

In order to answer this question, first we need to know how many bolts per second are produced by each machine, this can be known by dividing the number of bolts by the time it takes.

For machine A:

A = \frac{120 bolts}{40 s}= 3 \frac{bolts}{s}

For machine B:

B = \frac{100 bolts}{20 s}= 5 \frac{bolts}{s}

So, if the two machines run simultaneously, we will have a rate of prodcution of bolts equal to the sum of both:

A+B=(3+5)\frac{bolts}{s}=8\frac{bolts}{s}

Now, we need to know how much time it will take to producee 200 bolts, to find this out we need to divide the amount of bolts by the production rate:

t = \frac{bolts}{ProductionRate}= \frac{200 bolts}{8 \frac{bolts}{s} }

The <em>bolts</em> unit cancell each other and we are left with <em>seconds</em>

t = \frac{200}{8} s = 25 s

So it will take 25 seconds to produce 200 bolts with machine A and B running simultaneously.

Greetings!

4 0
3 years ago
Read 2 more answers
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