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Gnesinka [82]
3 years ago
13

How to write 15/1000

Mathematics
1 answer:
a_sh-v [17]3 years ago
4 0
0.015 or 3/200
15 divided by 1000 is 0.015
15/5 is 3 1000/5 is 200
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Please answer this question fast in two minutes
almond37 [142]

Answer:

∠CGA or ∠DGF

Step-by-step explanation:

Supplementary angles add up 180°

∠CGD + ∠CGA = 180°

∠CGD + ∠DGF = 180°

8 0
3 years ago
What are the solutions to the quadratic equation <img src="https://tex.z-dn.net/?f=x%5E2%20%2B40%3D0" id="TexFormula1" title="x^
Mandarinka [93]

Answer:

In disguise right arrow In Standard Form a, b and c

x2 = 3x − 1 Move all terms to left hand side x2 − 3x + 1 = 0 a=1, b=−3, c=1

2(w2 − 2w) = 5 Expand (undo the brackets),

and move 5 to left 2w2 − 4w − 5 = 0 a=2, b=−4, c=−5

z(z−1) = 3 Expand, and move 3 to left z2 − z − 3 = 0 a=1, b=−1, c=−3

Step-by-step explanation:

sorry it took so long

7 0
3 years ago
Help meee please <br><img src="https://tex.z-dn.net/?f=%20%20%5Csqrt%7B%3F%7D%20%7B78%7D%20%7D%20" id="TexFormula1" title=" \sq
tekilochka [14]
I think it is 8.83? I am not positive but it is worth a try
7 0
2 years ago
According to the National Association of Colleges and Employers, the average starting salary for new college graduates in health
katen-ka-za [31]

Answer:

a) The probability that a new college graduate in business will earn a starting salary of at least $65,000 is P=0.22965 or 23%.

b) The probability that a new college graduate in health sciences will earn a starting salary of at least $65,000 is P=0.11123 or 11%.

c) The probability that a new college graduate in health sciences will earn a starting salary of less than $40,000 is P=0.14686 or 15%.

d) A new college graduate in business have to earn at least $77,133 in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences.

Step-by-step explanation:

<em>a. What is the probability that a new college graduate in business will earn a starting salary of at least $65,000?</em>

For college graduates in business, the salary distributes normally with mean salary of $53,901 and standard deviation of $15,000.

To calculate the probability of earning at least $65,000, we can calculate the z-value:

z=\frac{x-\mu}{\sigma} =\frac{65000-53901}{15000} =0.74

The probability is then

P(X>65,000)=P(z>0.74)=0.22965

The probability that a new college graduate in business will earn a starting salary of at least $65,000 is P=0.22965 or 23%.

<em>b. What is the probability that a new college graduate in health sciences will earn a starting salary of at least $65,000?</em>

<em />

For college graduates in health sciences, the salary distributes normally with mean salary of $51,541 and standard deviation of $11,000.

To calculate the probability of earning at least $65,000, we can calculate the z-value:

z=\frac{x-\mu}{\sigma} =\frac{65000-51541}{11000} =1.22

The probability is then

P(X>65,000)=P(z>1.22)=0.11123

The probability that a new college graduate in health sciences will earn a starting salary of at least $65,000 is P=0.11123 or 11%.

<em>c. What is the probability that a new college graduate in health sciences will earn a starting salary less than $40,000?</em>

To calculate the probability of earning less than $40,000, we can calculate the z-value:

z=\frac{x-\mu}{\sigma} =\frac{40000-51541}{11000} =-1.05

The probability is then

P(X

The probability that a new college graduate in health sciences will earn a starting salary of less than $40,000 is P=0.14686 or 15%.

<em />

<em>d. How much would a new college graduate in business have to earn in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences?</em>

The z-value for the 1% higher salaries (P>0.99) is z=2.3265.

The cut-off salary for this z-value can be calculated as:

X=\mu+z*\sigma=51,541+2.3265*11,000=51,541+25,592=77,133

A new college graduate in business have to earn at least $77,133 in order to have a starting salary higher than 99% of all starting salaries of new college graduates in the health sciences.

8 0
3 years ago
Help and explain please and thankyouuu’!!!!!
Zarrin [17]

<em>here</em><em>,</em>

<em>f</em><em>(</em><em>x</em><em>)</em><em>=</em><em>x</em><em>-</em><em>4</em>

<em>then</em><em>,</em><em> </em><em>f</em><em>(</em><em>-</em><em>3</em><em>.</em><em>2</em><em>)</em><em>=</em><em>(</em><em>-</em><em>3</em><em>.</em><em>2</em><em>)</em><em>-</em><em>4</em>

<em>[</em><em> </em><em>replace</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>x</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>e</em><em>quation</em><em> </em><em>by</em><em> </em><em>-</em><em>3</em><em>.</em><em>2</em><em>]</em>

<em>therefore</em><em>,</em><em>f</em><em>(</em><em>-</em><em>3</em><em>.</em><em>2</em><em>)</em><em>=</em><em>-</em><em>7</em><em>.</em><em>2</em><em> </em><em>answer</em><em>.</em><em>.</em><em>.</em><em>.</em>

<em>HOPE</em><em> </em><em>THIS</em><em> </em><em>HELPS</em><em> </em><em>YOU</em><em>.</em><em>HAVE</em><em> </em><em>A</em><em> </em><em>NICE</em><em> </em><em>DAY</em><em>/</em><em>NIGHT</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

3 0
2 years ago
Read 2 more answers
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