Remember that -csc^2(x) is a known derivative; it is the derivative of cot(x).
<span>Keeping that in mind, let's put a negative there, and then offset it with another negative, which can conveniently be placed outside of the integral. </span>
<span>(-1) Integral ( -csc^2(x) dx ) </span>
<span>Which evaluates to </span>
<span>(-1) cot(x) + C </span>
<span>-cot(x) + C</span>
False. the minimum is just to hold off, it’s not forever. it will keep you in good condition, but not for the long run.
Tanner preformed 56 times last year. 50% is half so you just have to multiply 28 by 2
Step-by-step explanation:
- First step you take 25 on the other side and when it goes on other side it change the sign to negative 13x< -1-25
- second step you keep the sign of the bigger number then you add. The result will be 13x< -26
- third step you divide both side by 13x÷-26
- finally the answer will be -2
