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valina [46]
2 years ago
14

Round 3/7 to its closest benchmark

Mathematics
1 answer:
inna [77]2 years ago
6 0

Answer:

1/4 3/4 1/2.

it could be any of the above

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The weight distribution of parcels sent in a certain manner is normal with meanvalue 12 pounds and standard deviation 3.5 pounds
tino4ka555 [31]

Answer:

The parcel with weight less than 20.14 pounds are 99% of all parcels under the surcharge weight.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 12 pounds

Standard Deviation, σ = 3.5 pounds

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.99

P( X < x) = P( z < \displaystyle\frac{x - 12}{3.5})=0.99  

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 12}{3.5} = 2.326\\\\x = 20.141\approx 20.14  

Thus, parcel with weight less than 20.14 pounds are 99% of all parcels under the surcharge weight.

7 0
3 years ago
32) Find the value of 5x° + 2x-1 when x = 4.
SashulF [63]

Answer:

5x4°x7

Step-by-step explanation:

5x°+2x-1 when x =4

5x4°+2x4-1

5x4°+8-1

=5x4°x7

5 0
3 years ago
Write each of the rations below<br>In their simplest form<br>9:15​
creativ13 [48]

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8 0
3 years ago
How do you figure this out?
pantera1 [17]

3 ^{ - 2}  =  \frac{1}{3 {}^{2} }  =  \frac{1}{9}
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C (X,Y)->(X-4,×-5) I would say bro

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