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djverab [1.8K]
3 years ago
9

Write this decimal in numbers. thirty-five and twenty-one hundredths

Mathematics
2 answers:
kykrilka [37]3 years ago
4 0
35.21

explanation; the decimal always comes where it says “and”
Sholpan [36]3 years ago
3 0

Answer:

0.35

8448

I think that's the answer

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Answer: the correct answer is letter D, I just took the test and got it right on edg

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34. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.
skad [1K]

Answer:

The linear equation for the line which passes through the points given as (-1,4) and (5,2), is written in the point-slope form as $y=\frac{1}{3} x-\frac{13}{3}$.

Step-by-step explanation:

A condition is given that a line passes through the points whose coordinates are (-1,4) and (5,2).

It is asked to find the linear equation which satisfies the given condition.

Step 1 of 3

Determine the slope of the line.

The points through which the line passes are given as (-1,4) and (5,2). Next, the formula for the slope is given as,

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute 2&4 for $y_{2}$ and $y_{1}$ respectively, and $5 \&-1$ for $x_{2}$ and $x_{1}$ respectively in the above formula. Then simplify to get the slope as follows,

m=\frac{2-4}{5-(-1)}$\\ $m=\frac{-2}{6}$\\ $m=-\frac{1}{3}$

Step 2 of 3

Write the linear equation in point-slope form.

A linear equation in point slope form is given as,

$y-y_{1}=m\left(x-x_{1}\right)$

Substitute $-\frac{1}{3}$ for m,-1 for $x_{1}$, and 4 for $y_{1}$ in the above equation and simplify using the distributive property as follows,

y-4=-\frac{1}{3}(x-(-1))$\\ $y-4=-\frac{1}{3}(x+1)$\\ $y-4=-\frac{1}{3} x-\frac{1}{3}$

Step 3 of 3

Simplify the equation further.

Add 4 on each side of the equation $y-4=\frac{1}{3} x-\frac{1}{3}$, and simplify as follows,

y-4+4=\frac{1}{3} x-\frac{1}{3}+4$\\ $y=\frac{1}{3} x-\frac{1+12}{3}$\\ $y=\frac{1}{3} x-\frac{13}{3}$

This is the required linear equation.

5 0
2 years ago
Given the following two statements, what conclusion can be made? Three noncollinear points determine a plane. Points S, O, N are
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Actually, this has little to do with mathematics and geometry but has to do more with logical reasoning. You have two clauses to get a conclusion from. The reasoning is as follows:

Clause 1: <span>Three noncollinear points determine a plane
Clause 2: </span><span>Points S, O, N are noncollinear
</span>Conclusion: Therefore, points S, O and N form a plane.
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3 years ago
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katovenus [111]
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Toby has a suitcase. The suitcase’s length is 5 inches and the width is 8 inches. Find the area of a suit case.
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Step-by-step explanation:

area = lenght × breadth

area = 5×8

area = 40

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3 years ago
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