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Evgen [1.6K]
3 years ago
9

A group of 13 friends were planning a trip. On the night before they left they made a lot of phone calls. Each friend talked to

every friend at least once. What is the fewest phone calls that would have been made.
Mathematics
1 answer:
gavmur [86]3 years ago
6 0
I believe 156 because each person would have had to make 12 phone calls and there are 13 people so 12x13
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Let f(x) = log(x). Find values of a such that f(kaa) = kf(a).
meriva

Answer:

a = k^{\frac{1}{k-2}}

Step-by-step explanation:

Given:

f(x) = log(x)

and,

f(kaa) = kf(a)

now applying the given function, we get

⇒ log(kaa) = k × log(a)

or

⇒ log(ka²) = k × log(a)

Now, we know the property of the log function that

log(AB) = log(A) + log(B)

and,

log(Aᵇ) = b × log(A)

Thus,

⇒ log(k) + log(a²) = k × log(a)         (using log(AB) = log(A) + log(B) )

or

⇒ log(k) + 2log(a) = k × log(a)            (using log(Aᵇ) = b × log(A) )

or

⇒ k × log(a) - 2log(a) = log(k)

or

⇒ log(a) × (k - 2) = log(k)

or

⇒ log(a) = (k - 2)⁻¹ × log(k)

or

⇒ log(a) = \log(k^{\frac{1}{k-2}})          (using log(Aᵇ) = b × log(A) )

taking anti-log both sides

⇒ a = k^{\frac{1}{k-2}}

3 0
3 years ago
Find the coordinates of point P that lies along the directed line segment AB in a 2:3 ratio given A (-2, 1), B (3, 4).
saul85 [17]

Answer:

P(x,y) = (0,\frac{11}{5})

Step-by-step explanation:

Given

A = (-2,1)

B = (3,4)

m:n = 2:3

Required

Determine the coordinates of P

The coordinate of a point when divided into ratio is:

P(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})

Where

(x_1,y_1) = (-2,1)

(x_2,y_2) = (3,4)

m:n = 2:3

This gives:

P(x,y) = (\frac{2 * 3 + 3 * -2}{2 + 3},\frac{2 * 4 + 3 * 1}{2 + 3})

P(x,y) = (\frac{6 - 6}{5},\frac{8 + 3}{5})

P(x,y) = (\frac{0}{5},\frac{11}{5})

P(x,y) = (0,\frac{11}{5})

5 0
3 years ago
Function Operations Picture attached
sergeinik [125]

Answer: Second option

Step-by-step explanation:

You need to make the multiplication of the function c(x)=\frac{5}{x-2} and the function d(x)=x+3. Then:

(cd)(x)=(\frac{5}{x-2})(x+3)

You need to apply the Distributive property:

(cd)(x)=\frac{5(x+3)}{x-2}\\\\(cd)(x)=\frac{5x+15}{x-2}

Therefore, the domain will be all the number that make the denominator equal to zero.

Then, make the denominator equal to zero and solve for x:

x-2=0\\x=2

Therefore, the domain is: All real values of x except x=2

6 0
3 years ago
Identify the degree of the polynomial 6xy2 − xy + 8 + 12y.
Troyanec [42]
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3 years ago
A school is preparing a trip for 400 students. The company who is providing the transportation has 10 buses of 50 seats each and
Naya [18.7K]
<h2>The number of small buses used = 5</h2><h2>The number of big buses used  = 4</h2>

Step-by-step explanation:

Let us assume the total number of small buses needed = x

The capacity of 1 small bus  = 40

So, the capacity of x buses  = 40(x)  = 40 x

Let us assume the total number of big buses needed = y

The capacity of 1 big bus  = 50

So, the capacity of y buses  = 50(y)  = 50 y

Also, the total students travelling = 400

So, the number of students traveling by (Small bus + Big bus)  = 400

⇒ 40 x + 50 y = 400 ..... (1)

Also, the total number of drivers available  = 9

⇒ x +  y = 9  ..... (2)

Also, x  ≤ 8,   y ≤ 10

Now, solving both equations, we get:

40 x + 50 y = 400 ..... (1)

x +  y = 9  ⇒ y = (9-x) put in (1)

40 x + 50 y = 400  ⇒  40 x  + 50 (9-x)  = 400

or, 40 x  + 450 - 50 x  = 400

or, - 10 x  =- 50

or, x  = 5 ⇒ y = (9-x)  = 9- 5 = 4

Hence the number of small buses used = 5

The number of big buses used  = 4

8 0
3 years ago
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