Find a 92.9% confidence interval for the difference p1−p2p1−p2 of the population proportions.
Hint: For a level of confidence (1−α)⋅100%(1−α)⋅100%, z∗z∗ is the value that leaves an area of (1−α)/2(1−α)/2 to its right in a standard normal distribution
I hope that helps
Answer:
D) 
Explanation provided above.
Answer:
8x-6
Step-by-step explanation:
3(x-2)+5x = 3x - 6 +5
A.) v = πr^2h
v = π (20^2) * 50
v = π (400*50)
v = 20,000π
B.) v = πr^2h
v = π (4^2) * 10
v = π (16*10)
v = 160π
C.) 20,000π ÷ 160π = 125π
So, it can fill 125 mugs.
Answer:
x=5
Step-by-step explanation:
