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3 years ago

which of the following are the building blocks of geometry, according to hilbert? ray line angle point plane

Mathematics

2 answers:

statuscvo [17]3 years ago

8 0

The building blocks of geometry would be point line and plane.

AleksAgata [21]3 years ago

8 0

Answer: line point plane

Step-by-step explanation:

We know that there are three undefined terms in geometry which we use to define other terms in geometry.

The three undefined terms in the geometry :-

a) Point b) Line c) Plane

According to Hilbert , the above three undefined terms in the geometry are the building blocks of geometry which are use to build the entire geometry .

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Decimal 0.003 is 1/10 of

Grace [21]

Just multiply the 0.003 by 10 and you'll get the result. The easiest way to multiply such numbers is to move the dot one position to the right (it would be 2 positions if multiplied by 100, 3 by 1000 etc.). You can do the same with dividing, just remember to move to the left then.

So 0.03 is your answer

<span>Hope I Helped!!!</span>

6 0

3 years ago

Line A passes through the points (-1, 4) and (4, 9). Line B passes through the points (4, -4) and (-3, 24). Find the point where

exis [7]

A calculator can help

7 0

3 years ago

Read 2 more answers

$0.15, $0.30, $0.50, $0.75, $0.89<br> I need to know the percent of change for these numbers

Naddik [55]

Answer:

15% 30% 50% 75% 89%

Step-by-step explanation:

u change 0.15 to a function 15/100 then the one hungred below is persent

5 0

3 years ago

Harry is trying to solve the equation 0 = 2x2 − x − 6 using the quadratic formula. He has made an error in one of the steps belo

bija089 [108]

<h3><u>Given</u> - </h3>

➙ a quadratic equation in which Harry lagged due to an error made by him, 2x² - x - 6= 0

<h3><u>To solve</u> - </h3>

➙ the given quadratic equation.

<h3><u>Concept applied</u> - </h3>

➙ We will apply the quadratic formula as given in the question. So, let's study about quadratic equation first because we are supposed to apply the formula in equation.

What is quadratic equation?

➙ A quadratic equation in the variable x is an equation of the form ax² + bx + c = 0, where a, b, c are real numbers, a ≠ 0.

Now, what is quadratic formula?

➙The roots of a quadratic equation ax + bx + c = 0 are given by $\sf{\:\frac{-b \pm\: \sqrt {b ^ 2 - 4ac}}{2a}}$ provided b - 4ac ≥ 0.

<h3><u>Solution</u> - </h3>

here as per the given quadratic equation,

a = 2, b = -1 and c = -6

putting in the formula,

$\implies\sf{x=\frac{-(-1) \pm\: \sqrt {(-1)^2 - 4(2)(-6)}}{2(2)}}$

$\implies\sf{x=\frac{1 \pm\: \sqrt {1+48}}{4}}$

$\implies\sf{x=\frac{1 \pm\: \sqrt {49}}{4}}$

$\implies\sf{x=\frac{1 \pm\: 7}{4}}$

Solving one by one,

$\implies\sf{x=\frac{1 + \: 7}{4}}$

$\implies\sf{x=\frac{8}{4}}$

$\implies{\boxed{\bf{x=2}}}$

________________

$\implies\sf{x=\frac{1 - \: 7}{4}}$

$\implies\sf{x=\frac{-6}{4}}$

$\implies{\boxed{\bf{x=\frac{-3}{2}}}}$

________________________________

<em><u>Note</u> - Hey dear user!! You haven't provided the solution which was solved by Harry (A.T.Q). Please go through the solution as it will help you to find the error done by Harry.</em>

Hope it helps!! (:

4 0

2 years ago

Select the correct answer from each drop-down menu. the equation from the graphed line in slope-point form using the point 2,-1

Arada [10]

The formula for point-slope form is y-a=m(x-c), where y and x are variables, a is simply one point in y, m is the slope, and c is simply one point in x. The first thing we can find is m, or the slope. This is found by dividing the change in y over the change in x. The equation for this is (I’ll plug the points in the equation)
$\frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{y_{1}-y_{2}}{x_{1}-x_{2}} = \frac{-1-(-2)}{2-(-2)}= \frac{-1+2}{2+2} =1/4$

Therefore, our answer is the bottom one as our slope is 1/4.

Feel free to ask further questions!

5 0

3 years ago

Read 2 more answers