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Rainbow [258]
3 years ago
5

The point (3, 18) is on the parabola y =

Mathematics
1 answer:
liberstina [14]3 years ago
8 0

Answer:

y =  {ax}^{2}  \\ 18 = (a \times  {3}^{2} ) \\ 18 = 9a \\ a = 2

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If you add 17 to an even number, the answer will be even.<br> OA. True<br> OB. False
Rama09 [41]

Answer:

the answer is false because it will always be a odd number

4 0
1 year ago
Read 2 more answers
Which point, (5/2, 3) or (3/2, 20), is on the graph of 2x - 2/3y =3?<br><br> show steps pls!
Anna11 [10]
You should try both points
put  x=5/2 and y=3
5-2=3
the first one is on the graph
put  x=3/2 and y=20
3-40/3≠3
the second one is not on the graph


4 0
3 years ago
So yall... what's up?
Alexeev081 [22]
I believe it is option choice A, because that is the most reasonable and efficient
3 0
3 years ago
Camilo practica tiro al blanco. En cada disparo acertado puede obtener 5, 8, o 10 puntos. En su última práctica, su puntuación t
Radda [10]

Answer:

20 disparos

Step-by-step explanation:

Primera etapa es de determinar cuantos tiros de Camilo acertaron al blanco.

Sabemos que en su última práctica, obtuvo 99 puntos con una mezcla de 5, 8 y 10 puntos.  Eso puedo se exprimir así:

5x + 8y + 10x = 99

Sabemos también que el obtuvo tantos tiros de 8 puntos que de 10 puntos, entonces

y = z

Podemos mezclar las 2 ecuaciones y substituir y por z:

5x + 8y + 10y = 99

5x +18y = 99

Una ecuación, dos variables... no es fácil... pero son números pequeños y se puede intentar soluciones.  Entonces, cuantas veces podemos multiplicar 5 y 18 para obtener 99?

El más simple es de hacer la tabla de multiplicación de 18 y ver cual número nos deja con un multiple de 5.

18 x 1 = 18 (99 - 18 = 81, no un multiple e 5)

18 x 2 = 36 (99 - 36 = 63, no un multiple de 5)

18 x 3 = 54 (99 - 54 = 45, SI, un multiple de 5)

18 x 4 = 72 (99 - 72 = 27, no un multiple de 5)

18 x 5 = 90 (99 - 90 = 9, no un multiple de 5)

Entonces, sabemos que y = 3 y z = 3

5x + 18 (3) = 99

5x + 54 = 99

5x = 45

x = 9

El tiró 9 veces por 5 puntos, 3 veces por 8 puntos y 3 veces pour 10 puntos.

En total tiró 15 veces.

Si acertó 75% (3/4) de las veces, cuantos tiros total?

\frac{15}{3/4} = \frac{15 * 4}{3} = 20

Camilo tiró 20 veces en total.

8 0
3 years ago
Atmospheric pressure decreases by about 11.8% for every 1000 meters you climb. The pressure at sea level is 1013 millibars (a un
erica [24]
At sea level, the pressure is 1013, that's when the altitude is at 0, sea level, let's see

\bf \textit{Periodic Exponential Decay}\\\\&#10;A=I(1 - r)^{\frac{t}{p}}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &1013\\&#10;I=\textit{initial amount}\\&#10;r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\&#10;t=\textit{meters climbed}\to &0\\&#10;p=period\to &1000&#10;\end{cases}&#10;\\\\\\&#10;1013=I(1-0.118)^{\frac{0}{1000}}\implies 1013=I\cdot 1\implies 1013=I

so, the inital amount is 1013, when t = 0,

\bf \textit{Periodic Exponential Decay}\\\\&#10;A=I(1- r)^{\frac{t}{p}}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;I=\textit{initial amount}\to &1013\\&#10;r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\&#10;t=\textit{meters climbed}\to &t\\&#10;p=period\to &1000&#10;\end{cases}&#10;\\\\\\&#10;A=1013(1-0.118)^{\frac{t}{1000}}\implies A=1013(0.882)^{\frac{t}{1000}}

now, to check the atmospheric pressure at 4000, simply set t = 4000, to get A.


7 0
3 years ago
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